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Reil [10]
3 years ago
9

Explain how to get the product of 2 times the square root of 5 and 4 times the square root of 10

Mathematics
1 answer:
Vlad1618 [11]3 years ago
6 0
The square root of 5 is 2.2 and 4 times the square root of 10 is 100
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Find the length of each arc. Round your answers to the nearest tenth.
suter [353]
brainly.com/question/18907766
3 0
3 years ago
Solve the following proportion for v. <br>8/5 = v/6 <br>Round your answer to the nearest tenth.​
bekas [8.4K]

Answer:

v=\frac{48}{5}=9\frac{3}{5} \\

Step-by-step explanation:

\frac{8}{5}=\frac{v}{6}

Swap sides:

\frac{v}{6}=\frac{8}{5}

Multiply to both sides by 6:

\frac{v}{6}\cdot6=\frac{8}{5}\cdot6

Group like terms:

\frac{1}{6}\cdot6v=\frac{8}{5}\cdot6

Simplify the fraction:

v=\frac{8}{5}\cdot6

Multiply the fractions

v=\frac{8\cdot6}{5}

Simplify the arithmetic:

v=\frac{48}{5}

4 0
2 years ago
Plzzzzzzzz help for a brainly
ANTONII [103]

Answer:

246

Step-by-step explanation:

5 0
2 years ago
Which expression has a value different from the others?
Alexxandr [17]

Answer:

I think B

Step-by-step explanation:

A. -108+105

-3

B. 9.9+(12.9)

22.8

C. -7 2/9 -(-4 2/9)

-3

D. 637 - 641

-4

Is the last one written wrong because if that one is 637-640 or 638-641 than it would equal -3. Then the answer would be B.

5 0
3 years ago
There are eight wires which need to be attached to a circuit board. A robotic device will attach the wires. The wires can be att
Illusion [34]

Answer: 40320 sequence to test.

Step-by-step explanation:

we have given the following data:

No of wires which need to be attached to a circuit board = 8

What We need to find is the number of possible sequences of assembly that must be tested.

Using our multiplication rule of counting we arrive at,

Number of possible sequences of assembly is given by

8! = 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1

= 40320

i.e. there are 8 choices for the first wire, 7 choices for the second wire, 6 choices for the third wire, 5 choice for the fourth wire same till the 8th wire.

Hence, there are 40320 possible sequences of assembly.

3 0
3 years ago
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