Explain how to get the product of 2 times the square root of 5 and 4 times the square root of 10

Mathematics

1 answer:

Vlad1618 [11]3 years ago

6 0

The square root of 5 is 2.2 and 4 times the square root of 10 is 100

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Evaluate the integral. (sec2(t) i t(t2 1)8 j t7 ln(t) k) dt

polet [3.4K]

If you're just integrating a vector-valued function, you just integrate each component:

$\displaystyle\int(\sec^2t\,\hat\imath+t(t^2-1)^8\,\hat\jmath+t^7\ln t\,\hat k)\,\mathrm dt$

$=\displaystyle\left(\int\sec^2t\,\mathrm dt\right)\hat\imath+\left(\int t(t^2-1)^8\,\mathrm dt\right)\hat\jmath+\left(\int t^7\ln t\,\mathrm dt\right)\hat k$

The first integral is trivial since $(\tan t)'=\sec^2t$ .

The second can be done by substituting $u=t^2-1$ :

$u=t^2-1\implies\mathrm du=2t\,\mathrm dt\implies\displaystyle\frac12\int u^8\,\mathrm du=\frac1{18}(t^2-1)^9+C$

The third can be found by integrating by parts:

$u=\ln t\implies\mathrm du=\dfrac{\mathrm dt}t$

$\mathrm dv=t^7\,\mathrm dt\implies v=\dfrac18t^8$

$\displaystyle\int t^7\ln t\,\mathrm dt=\frac18t^8\ln t-\frac18\int t^7\,\mathrm dt=\frac18t^8\ln t-\frac1{64}t^8+C$

8 0

3 years ago

7 divided into 2 what's the answer

Alex17521 [72]

3.5 hope this helps C:

4 0

3 years ago

Read 2 more answers

What two-dimensional figure will result from slicing this rectangular pyramid parallel to the base?

andreev551 [17]

Answer: The answer is D. Trapezoid.

Step-by-step explanation: As shown in the attached figure, a rectangular pyramid ABCDE is drawn. We are slicing this rectangular pyramid parallel to the base BCDE at the points F, G, H and I.

We can clearly see from the figure that upper half of the sliced figure will be similar to the pyramid BCDE and the lower sliced figure will be a trapezoid. These are the three-dimensional figures.

Also, the sliced two-dimensional figure FGHI will be a rectangle, because

the pyramid is a rectangular one and so, FI=GH, FG=HI and all the angles are right angles.

Thus, the resulting two-dimensional figure will be a rectagle.