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tia_tia [17]
3 years ago
6

5002190 in expanded firm

Mathematics
2 answers:
bezimeni [28]3 years ago
6 0
5000000 000000 0000 2000 100 90 0 i hope this helps
ladessa [460]3 years ago
4 0
5,000,000+2000+100+90
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PLEASEEEE ANSWER ASAP
Alona [7]

Answer:

x = -1, x = 1

Step-by-step explanation:

Factor the equation. (It's a difference of squares, so we know the form will be (a-b)(a+b).)

y = x^{2} - 1\\y = (x-1)(x+1)

Test this by FOILing it out, if you're unsure. This is something it can be good to memorize!

Set it equal to 0.

0 = (x+1)(x-1)

Separate the two parenthetical expressions by the Zero Product Property.

0 = x+1\\0 = x-1

Solve for x!

x=-1, x=1

3 0
3 years ago
35 is 29% of what number
ladessa [460]

Answer:

10.15 is 29% of 35.

Step-by-step explanation:

7 0
3 years ago
I need help on c please bad!
Mama L [17]

Answer:

Step-by-step explanation:

The submarine is underwater for 6 seconds. The submarine hits the water after 1 second and comes back up at the 7th second.

3 0
3 years ago
Use the graph of f '(x) below to find the x values of the relative maximum on the graph of f(x):
Lana71 [14]

Answer:

You have relative maximum at x=1.

Step-by-step explanation:

-Note that f' is continuous and smooth everywhere. f therefore exists everywhere on the domain provided in the graph.

f' is greater than 0 when the curve is above the x-axis.

f' greater than 0 means that f is increasing there.

f' is less than 0 when the curve is below the x-axis.

f' is less than 0 means that f is decreasing there.

Since we are looking for relative maximum(s), we are looking for when the graph of f switches from increasing to decreasing. That forms something that looks like this '∩' sort of.

This means we are looking for when f' switches from positive to negative. At that switch point is where we have the relative maximum occurring at.

Looking at the graph the switch points are at x=0, x=1, and x=2.

At x=0, we have f' is less than 0 before x=0 and that f' is greater than 0 after x=0.  That means f is decreasing to increasing here. There would be a relative minimum at x=0.

At x=1, we have f' is greater than 0 before x=1 and that f' is less than 0 after x=1. That means f is increasing to decreasing here. There would be a relative maximum at x=1.

At x=2, we have f' is less than 0 before x=2 and that f' is greater than 0 after x=2. That means f is decreasing to increasing here. There would be a relative minimum at x=2.

Conclusion:

* Relative minimums at x=0 and x=2

* Relative maximums at x=1

3 0
3 years ago
Seth bought a 12 ounce jar of peanut butter for $ 3.60. What is the unit price?
svetlana [45]

Answer:

30

Step-by-step explanation:

7 0
3 years ago
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