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trapecia [35]
3 years ago
10

The graph below shows the quadratic function f, and the table below shows the quadratic function g.

Mathematics
1 answer:
valkas [14]3 years ago
5 0
I think the correct answer is D), I’m sorry if it’s wrong
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What is Pi times Pi.
Delvig [45]

Answer:

pi * pi 9.86960440109

Step-by-step explanation:

7 0
3 years ago
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Which inequality does the graph below represent?
Dima020 [189]

Answer:

A. y\le2x^2-8x+3

Step-by-step explanation:

The given parabola has vertex at (2,-5).

The equation of this parabola in vertex form is given by:

y=a(x-h)^2+k, where (h,k)=(2,-5) is the vertex  of the parabola.

We substitute the values to get:

y=a(x-2)^2-5

The graph passes through; (0,3).

3=a(0-2)^2-5

\implies 3+5=4a

\implies 8=4a

\implies a=2

Hence the equation of the parabola is

y=2(x-2)^2-5

We expand this to get:

y=2x^2-8x+8-5

y=2x^2-8x+3

Since the outward region was shaded, the corresponding inequality is

y\le2x^2-8x+3

The correct answer is A

7 0
3 years ago
Please help me <br>please please ​
Rom4ik [11]

Answer:

I did it hope you will understand

7 0
3 years ago
A random sample of 30 seventh grade students shows that 12 of them own a dog. How many seventh grade students can you predict ow
ArbitrLikvidat [17]

Answer:

160

Step-by-step explanation:

If out of 30 7th graders, 12 own a dog then when you have 400 of them, 160 will have a dog as well.

The way I did this was by 400/30: which was 13.3 repeating. I then mutliplied this number by 12, to find the final answer of 160.

4 0
3 years ago
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18 cajas de manzanas y peras fueron llevadas a la escuela. Las peras trajeron 210 kg en 6 cajas. ¿Cuántos kilos de manzanas fuer
Katyanochek1 [597]

Answer:

504 kilos de manzanas fueron llevados a la escuela.

Step-by-step explanation:

Sean x, y la cantidad de cajas de manzanas y peras, respectivamente. De acuerdo con el enunciado, tenemos el siguiente sistema de ecuaciones:

Total de cajas

x+y = 18 (1)

Masa de cada caja de peras

y\cdot m_{P} = 210 (2)

y = 6 (3)

Masa de caja de manzanas

m_{M} = m_{P}+7 (4)

De (2) en (3), tenemos que la masa de cada caja de peras es:

m_{P} = 35\,kg

Por (4), encontramos que la masa de cada caja de manzanas es:

m_{M} = 35\,kg+7\,kg

m_{M} = 42\,kg

Finalmente, de (1) tenemos la cantidad de cajas de manzana:

x = 18-y

x = 12

La cantidad de kilos de manzanas llevada a la escuela se obtiene al multiplicar la cantidad de cajas de manzana por la masa de cada caja:

M = (12)\cdot (42\,kg)

M = 504\,kg

504 kilos de manzanas fueron llevados a la escuela.

7 0
2 years ago
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