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3 years ago

Which conversions go from a smaller unit to a larger unit? Select all that apply.

Mathematics

2 answers:

Butoxors [25]3 years ago

8 0

Answer:

decimeters to meters

Step-by-step explanation:

There are 10 decimeters in a meter.

Natali5045456 [20]3 years ago

5 0

Answer:

sr vsrfvsrfv

Step-by-step explanation:

fv srv srfrsf

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The ratio of lollipops to pieces of bubble gum at the party is 2 to 3. There are 24 lollipops. What is the total number of lo

disa [49]

Answer: 40

Step-by-step explanation: first make the ratio into a fraction, 2/3

then make 24 into a fraction with the numerator as a variable and the denominator as 24, x/24

then cross multiply 2 and 24.

2x24=48

then divide 48 by 3, 16.

last add the number of lollipops to 16 and the answer is 40.

5 0

2 years ago

Read 2 more answers

Calculate a four-day moving average for the price of the stock for the end of day 7. day 1 - 62.00; day 2 - 56.00; day 3 - 50.00

Aneli [31]

At day 7, the four-day moving average for the price of the stock would be $58.25.

<h3>What is the four-day moving average at day 7?</h3>

This can be found as:

= (Day 7 price + Day 6 + Day 5 + Day 4) / Number of days

Solving gives:

= (59 + 55 + 59 + 60) / 4

= 233 / 4

= $58.25

Find out more on moving averages at brainly.com/question/15188858.

#SPJ1

8 0

2 years ago

Suppose that the length of a side of a cube X is uniformly distributed in the interval 9

Nastasia [14]

Answer:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

Step-by-step explanation:

Given

$9 < x < 10$ --- interval

Required

The probability density of the volume of the cube

The volume of a cube is:

$v = x^3$

For a uniform distribution, we have:

$x \to U(a,b)$

and

$f(x) = \left \{ {{\frac{1}{b-a}\ a \le x \le b} \atop {0\ elsewhere}} \right.$

$9 < x < 10$ implies that:

$(a,b) = (9,10)$

So, we have:

$f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Solve

$f(x) = \left \{ {{\frac{1}{1}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Recall that:

$v = x^3$

Make x the subject

$x = v^\frac{1}{3}$

So, the cumulative density is:

$F(x) = P(x < v^\frac{1}{3})$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$ becomes

$f(x) = \left \{ {{1\ 9 \le x \le v^\frac{1}{3} - 9} \atop {0\ elsewhere}} \right.$

The CDF is:

$F(x) = \int\limits^{v^\frac{1}{3}}_9 1\ dx$

Integrate

$F(x) = [v]\limits^{v^\frac{1}{3}}_9$

Expand

$F(x) = v^\frac{1}{3} - 9$

The density function of the volume F(v) is:

$F(v) = F'(x)$

Differentiate F(x) to give:

$F(x) = v^\frac{1}{3} - 9$

$F'(x) = \frac{1}{3}v^{\frac{1}{3}-1}$

$F'(x) = \frac{1}{3}v^{-\frac{2}{3}}$

$F(v) = \frac{1}{3}v^{-\frac{2}{3}}$

So:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

8 0

2 years ago

How many ways can 6 people be chosen and arranged in a straight line if there are 8 people to choose from? 720 20,160 40,320 48?

Rudik [331]

The number of permutations of 8 people taken 6 at a time is given by:
$8P6=\frac{8!}{(8-6)!}=20,160
$

5 0

2 years ago

Read 2 more answers

Two angles are complementary. One angle is labeled 2p+6°. The other angles is labeled 4p°. Find the value of p.

makkiz [27]

Answer:

Value of p is 14

Step-by-step explanation:

$given \: complementary \: angles \: add \: up \: to \: 90 \: degrees \\ then \\ 2p + 6 + 4p = 90 \\ 6p + 6 = 90 \\ 6(p + 1) = 90 \\ p + 1 = \frac{90}{6} \\ p + 1 = 15 \\ p = 15 - 1 \\ p = 14$

HAVE A NICE DAY!

THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION. 

5 0

2 years ago