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lozanna [386]
3 years ago
6

PLEASE HELP ASAP!!!!Write the ratio as a fraction in lowest terms. 9 pounds to 36 pounds.(50 points!!)

Mathematics
2 answers:
blagie [28]3 years ago
6 0

Answer:

1/4

Step-by-step explanation:

9 lbs

---------

36 lbs

We can write this because the units are the same

Divide the top and bottom by 9

9/9

----------

36 /9

1/4

kobusy [5.1K]3 years ago
4 0

Answer:

1/4

Step-by-step explanation:

9 pounds

36 pounds

Ratios are written as x:y, fractions are written as x/y.

9:36 as a fraction will be 9/36

Simplify the fraction.

1/4

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The area of each circle is exactly
tekilochka [14]

Total area of the circle is 1.12π square inches.

<h3>What is Area of circle?</h3>

The Area of circle is π times the square of the radius.

i.e., A = πr²

Given:

Area of one circle = 0.56π

As the second circle is also identical then the area will be same.

So, the total area of circle is

=2* 0.56π

=1.12π square inches.

Learn more about area of circle here:

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4 0
1 year ago
PLEASE HELP ASAP!!! Explain, thank you-
Nat2105 [25]

Answer:

The answer to your question is:  \sqrt[4]{2^{3} } + 1

Step-by-step explanation:

\frac{1}{\sqrt[4]{2- 1}}  x \frac{\sqrt[4]{2^{3}}+ 1 }{\sqrt[4]{2^{3}} + 1}                       = [tex]\frac{\sqrt[4]{2^{3}}+ 1 }{2 - 1}  

                    = \sqrt[4]{2^{3} } + 1

6 0
3 years ago
Multiply.<br> 7.8 x 100<br> 7.83 x 10,000
luda_lava [24]
7.8 x 100 = 780
7.83 x 10,000 = 78,300
6 0
2 years ago
Read 2 more answers
If your grade is 81.89% and you get 30% on a hw whats your grade
ss7ja [257]

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Step-by-step explanation:

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At time t ≥ 0, the velocity of a body moving along the s-axis is v = t² -5t +4. When is the body moving backwards
katovenus [111]

Answer:

A

Step-by-step explanation:

The velocity of a moving body is given by the equation:

v=t^2-5t+4 ,\, t\geq0

Is the velocity is <em>positive </em>(v>0), then our object will be moving <em>forwards</em>.

And if the velocity is negative (v<0), then our object will be moving <em>backwards</em>.

We want to find between which interval(s) is the object moving backwards. Hence, the second condition. Therefore:

v

By substitution:

t^2-5t+4

Solve. To do so, we can first solve for <em>t</em> and then test values. By factoring:

(t-4)(t-1)=0

Zero Product Property:

t=1, \text{ and } t=4

Now, by testing values for t<1, 1<t<4, and t>4, we see that:

v(0)=4>0,\, v(2)=-20

So, the (only) interval for which <em>v</em> is <0 is the second interval: 1<t<4.

Hence, our answer is A.

7 0
3 years ago
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