All categories

3 years ago

2x + 5(3y * 8x) - 2 = 2x + 4y - 3

Mathematics

1 answer:

olga2289 [7]3 years ago

4 0

Answer:

x = 4y - 1/120y, y ≠ 0

Step-by-step explanation:

First, let's subtract 2x from both sides of the equation:

2x + 5 ⋅ 3y ⋅ 8x - 2 - 2x = 2x + 4y - 3 - 2x

Simplify:

5 ⋅ 3y ⋅ 8x - 2 = 4y - 3

Multiply the 5 ⋅ 3 ⋅ 8:

120xy - 2 = 4x - 3

Add 2 to both sides of the equation:

120xy - 2 + 2 = 4x -3 + 2

Simplify:

120xy = 4y - 1

Divide both sides by the 120y:

120xy/120y = 4y/120y = 1/120y; y ≠ 0

So,

x = 4y - 1/120y, y ≠ 0

I hope this helps!

(phew)

You might be interested in

Consider the graph below:

ladessa [460]

Answer:

y=-5/4x+5

Step-by-step explanation:

The line goes down 5 for every 4 to the right, and it crosses the y-axis at (0,5).

4 0

3 years ago

What is the slope, m, and the y-intercept of the line that is graphed below? On a coordinate plane, a line goes through points (

salantis [7]

Answer:

m = 1; (0, 3) is the correct answer.

Step-by-step explanation:

The general equation of a line is given by:

$y=mx+c$

where, m is the slope of line

c is the y-intercept and

(x,y) are the points from where the line passes.

We are given that the line passes through 2 points (-3,0) and (0,3).

Putting the values of (x,y) in the equation of line.

Putting (0,3):

$3 = m \times 0 + c\\\Rightarrow c =3$

So, y-intercept is (0,3).

Hence, equation of line becomes:

$y = mx + 3$

Putting (-3,0) in $y = mx + 3$ :

$0 = m(-3) +3\\\Rightarrow 3m = 3\\\Rightarrow m =1$

So, the equation of line becomes:

$y = x +3$

Please find attached graph.

m = 1; y intercept (0, 3) is the correct answer.

5 0

3 years ago

Read 2 more answers

Do these Functions change curvature? Y intercept? 1-f(x)+k 2-kf(x) 3-f(x+k) 4-f(kx)

Alina [70]

1 one change I don't know how but change

3 0

3 years ago

Find the first 5 terms of the sequence A(n)=n+A(n-1) a1 = 3

faust18 [17]

Answer:

A(1) = 3, A(2) = 5, A(3) = 8, A(4) = 12, A(5) = 17

Step-by-step explanation:

Given A(n) = n + A(n–1) a1 = 3.

A(1) = 3.

A(2) = (2) + A(2–1)

= (2) + A(1)

= (2) + (3) = 5

A(3) = (3) + A(3-1)

= (3) + A(2)

= (3) + (5) = 8

A(4) = (4) + A(4–1)

= (4) + A(3)

= (4) + (8) = 12

A(5) = (5) + A(5–1)

= (5) + A(4)

= (5) + (12) = 17

8 0

3 years ago

What is the distance between point (5, 9) and its reflection across the y-axis?

tamaranim1 [39]

Answer:

10 units

Step-by-step explanation:

Given: Point is $(5,9)$

To find: the distance between point $(5,9)$ and its reflection across the y-axis

Solution:

Reflection of point $(x,y)$ is $(-x,y)$ across the y-axis

So, reflection of point $(5,9)$ is $(-5,9)$ across the y-axis

Distance between points $(x_1,y_1),(x_2,y_2)$ is given by $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Let $(x_1,y_1)=(5,9),(x_2,y_2)=(-5,9)$

So,

the distance between point (5, 9) and its reflection across the y-axis = $\sqrt{(-5-5)^2+(9-9)^2}=\sqrt{100}=10$

Distance = 10 units

4 0

3 years ago