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Debora [2.8K]
2 years ago
12

What is the Area of this quadrilateral

Mathematics
1 answer:
snow_lady [41]2 years ago
8 0

C is the answer i just did this answer and get it correct

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This need to be correct plzzzzzzzzzzzz I got this answer wrong so send the new one
Novosadov [1.4K]

Answer:

$215,892.50

Step-by-step explanation:

This is a problem of compound interest.

In compound interest Amount A for principal p charged at interest r% per annum is given by

A = p(1+r/100)^n

where n is the time period in years.

_____________________________

given

p = $100,000

r = 8%

t = 10 years

A= 100,000( 1+ 8/100)^10

A= 100,000( 1.08)^10

A = $215,892.50

So , you need to pay $215,892.50 in total to debt cleared of debt.

4 0
3 years ago
An isosceles triangle has an angle that measures 26°. Which other angles could be in that
snow_tiger [21]

Answer:

26° 26° 128°

77° 77° 26°

Step-by-step explanation:

So we have two scenarios here.

One of them is if the base angles are 26°.

If that's true, the other angle is 128°

The other scenario is the opposite.

This means the base angles are 77°

5 0
2 years ago
Given the conditional statement c→~b, which of the following is the converse
exis [7]

Answer:

To form the converse of the conditional statement, interchange the hypothesis and the conclusion. The converse of "If it rains, then they cancel school" is "If they cancel school, then it rains." To form the inverse of the conditional statement, take the negation of both the hypothesis and the conclusion.

Step-by-step explanation:

3 0
3 years ago
Find the measure of each angle and tell which postulates or theorems you used <br> ?
Illusion [34]

Answer:

∠6=78° ∠7=102° ∠14=78°

Step-by-step explanation:

Angles 6 and 7 are supplementary angles so ∠a+∠b=180°

in this case it would be 102°+x=180° and you subtract 102° from 180° getting 78°

∠7 is the vertical angles postulate stating that any angles vertical to each other are eaqual

7 0
3 years ago
What are the roots of the quadratic equation x2+2x=-5
stiks02 [169]

Answer:

x = -1 +/-2i

Step-by-step explanation:

Write the equation in standard form to find the roots, also known as the solutions, zeros, or x-intercepts, of the quadratic.

x² + 2x + 5 = 0

Use the quadratic formula by substituting a= 1, b = 2 and c = 5.

x = \frac{-2 +/- \sqrt{(-2)^2 - 4(1)(5)} }{2(1)} = \frac{-2 +/-\sqrt{4 -20 } }{2} = \frac{-2 +/-\sqrt{-16 } }{2} = \frac{-2 +/-4i }{2} = -1 +/-2i

5 0
3 years ago
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