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Debora [2.8K]
3 years ago
12

What is the Area of this quadrilateral

Mathematics
1 answer:
snow_lady [41]3 years ago
8 0

C is the answer i just did this answer and get it correct

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Instructions: Rewrite the equation in proper Standard Form.
pochemuha
Standard form: x-3y=-12
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3 years ago
Using that formula
d1i1m1o1n [39]

20% x 50 =(20 / 100) x 50 = (20 x 50) / 100 = 1000 / 100 = 10

answer is 10

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Prove that the sets [0,1] [0,1) are equinumerous
expeople1 [14]
You are rigth because it just said that it is
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Give EG = 5x+7 EF =5x and FG=2x-7
Len [333]

Answer:

x = 7

42, 35, 7

Step-by-step explanation:

  • EG = 5x+7
  • EF = 5x  
  • FG = 2x-7

Point F is on line segment of EG, therefore EG = EF + FG

  • 5x + 7 = 5x + 2x - 7
  • 2x = 14
  • x = 7

Then

  • EG = 5*7 + 7 = 42
  • EF = 5*7 = 35
  • FG = 2*7 - 7 = 7
7 0
3 years ago
URGENT! PLEASE HELP.
uysha [10]

Answer: a) BC = 1386.8 ft

b) CD = 565.8 ft

Step-by-step explanation:

Looking at the triangle,

AD = BD + 7600

BD = AD - 7600

Considering triangle BCD, we would apply the the tangent trigonometric ratio.

Tan θ = opposite side/adjacent side. Therefore,

Tan 24 = CD/BD = CD/(AD - 700)

0.445 = CD/(AD - 700)

CD = 0.445(AD - 700)

CD = 0.445AD - 311.5 - - - - - - - -1

Considering triangle ADC,

Tan 16 = CD/AD

CD = ADtan16 = 0.287AD

Substituting CD = 0.287AD into equation 1, it becomes

CD = 0.445AD - 311.5

0.287AD = 0.445AD - 311.5

0.445AD - 0.287AD = 311.5

0.158AD = 311.5

AD = 311.5/0.158

AD = 1971.52

CD = 0.287AD = 0.287 × 1971.52

CD = 565.8 ft

To determine BC, we would apply the Sine trigonometric ratio which is expressed as

Sin θ = opposite side/hypotenuse

Sin 24 = CD/BC

BC = CD/Sin24 = 565.8/0.408

BC = 1386.8 ft

4 0
3 years ago
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