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mr Goodwill [35]
3 years ago
6

In a right triangle, the length of the hypotenuse is 20 inches and the length of one leg is 15 inches. What is the length of the

other leg in inches?
Mathematics
1 answer:
VikaD [51]3 years ago
7 0
Solutions 

To solve this problem we have to use the Pythagorean theorem. You can only use the Pythagorean theorem in Right Triangles. The longest side of the triangle is called the "hypotenuse". C² is the longest side so it is the hypotenuse . To calculate c² we have to do α² + β² = c². 

<span>Given 

</span><span>In a right triangle, the length of the hypotenuse is 20 inches and the length of one leg is 15 inches. 

</span>c^2 = 20 in &#10;

&#10;a^2 = 15 in
<span>
</span>&#10;b^2 = Unknown 

------------ Calculations 
<span>
</span>b^2 = c^2 - a^2  

b^2 = c^2(20) - a^2(15) 

b^2 = 400 - 225 

b^2 = 175 

b =  \sqrt{175} 

b = 13.2287565553 &#10; 


<span>

</span>
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Answer:

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Step-by-step explanation:

1 Quart = 32 Fluid Ounce

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4.75 Qt = 152 Fl. Oz.

3 0
3 years ago
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4 0
3 years ago
Help me fast!!!!!!!I need to finish this by next period
klio [65]

Answer:

-2/3

Step-by-step explanation:

Rise over run!  The slope rises twice and goes over 3 times.  The slope is negative so put a negative sign behind it.

3 0
2 years ago
Read 2 more answers
A. [4 marks]
storchak [24]

The value of d is -2

Step-by-step explanation:

The nth term of the arithmetic sequence is u_{n}=u_{1}+(n-1)d , where

  • u_{1} is the first term
  • d is the common difference between each 2 consecutive terms

The nth term of the geometric sequence is u_{n}=u_{1}r^{n-1} , where

  • u_{1} is the first term
  • r is the common ratio between each two consecutive terms r=\frac{u_{2}}{u_{1}}=\frac{u_{3}}{u_{2}}

∵ u_{1} of an arithmetic sequence is 1

∵ The common difference is d, where d ≠ 0

∵ u_{2} , u_{3} , u_{6} are the first 3 terms of a geometric sequence

∵ u_{2} = 1 + (2 - 1)d

∴ u_{2} = 1 + d

∵ u_{3} = 1 + (3 - 1)d

∴ u_{2} = 1 + 2d

∵ u_{6} = 1 + (6 - 1)d

∴ u_{2} = 1 + 5d

∴ The first 3 terms of the geometric sequence are (1 + d) , (1 + 2d) ,

   (1 + 5d)

∵ The common ratio in the geometric sequence is r=\frac{u_{2}}{u_{1}}=\frac{u_{3}}{u_{2}}

∴ r=\frac{1+2d}{1+d}=\frac{1+5d}{1+2d}

- Use cross multiplication with the equal fractions

∵ \frac{1+2d}{1+d}=\frac{1+5d}{1+2d}

∴ (1 + 2d)(1 + 2d) = (1 + d)(1 + 5d)

∴ 1 + 2d + 2d + 4d² = 1 + 5d + d + 5d²

- Add like terms in each side

∴ 1 + 4d + 4d² = 1 + 6d + 5d²

- Subtract 1 from both sides

∴ 4d + 4d² = 6d + 5d²

- Subtract 4d from both sides

∴ 4d² = 2d + 5d²

- Subtract 4d² from each side

∴ 0 = 2d + d²

- Take d as a common factor

∴ 0 = d(2 + d)

- Equate each factor by 0

∴ d = 0 but we will reject it because d ≠ 0

∴ 2 + d = 0

- Subtract 2 from both sides

∴ d = -2

The value of d is -2

Learn more:

You can learn more about the sequence in brainly.com/question/1522572

#LearnwithBrainly

7 0
3 years ago
There are 12 grams of sugar in 1⁄3 of a piece of candy. How much sugar is in 3⁄4 of a piece of candy?
lisov135 [29]

Answer:

27 grams of sugar

Step-by-step explanation:

If 1/3 candy contains 12 grams of sugar

Then 3/4 candy contains C grams of sugar

C= 3/4 * 12grams➗1/3=3*12*3grams➗4=108grams➗4=27 grams of sugar

4 0
3 years ago
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