Answer:
A) The value of a is <u>29</u>.
B) The value of b is <u>greater than 29</u>.
C) In both part A and part B we have used a common property which is addition property and that we have add 9 on both side of equation in both parts.
D) The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.
Step-by-step explanation:
Solving for Part A.
Given,

We have to solve for a.

By using addition property of equality, we will add both side by 9;

Hence the value of a is <u>29</u>.
Solving for Part B.
Given,

We have to solve for b.

By using addition property of inequality, we will add both side by 9;

Hence the value of b is <u>greater than 29</u>.
Solving for Part C.
In both part A and part B we have used a common property which is addition property and that we have add 9 on both side of equation in both parts.
Solving for Part D.
The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.
The first is the correct
Δ ZYB ≈ Δ OWR by SSS
because:
ZB = OR = 5
ZY = OW = 3
YB = WR = 5.5
Answer: -5x+-10 using the distributive property