For what purpose are high-level programming languages used for

1. Would it be possible for two people to have the same email address? Explain.

Goshia [24]

Answer: No

Explanation:

For the same reason that two people cannot have the same address, it's just a virtual address.

6 0

2 years ago

Read 2 more answers

Complete the AscendingAndDescending application so that it asks a user to enter three integers. Display them in ascending and de

Andreas93 [3]

Answer:

Following are the solution to the given question:

import java.util.Scanner;//import package

public class AscendingAndDescending//defining a class AscendingAndDescending

{

public static void main(String[] args) //main method

{

int n1,n2,n3,min,max,m;

Scanner in = new Scanner(System.in);//creating Scanner class object

System.out.print("Enter an integer: ");//print message

n1 = in.nextInt();//input value

System.out.print("And another: ");//print message

n2 = in.nextInt();//input value

System.out.print("And just one more: ");//print message

n3 = in.nextInt();//input value

min = n1; //use min variable that holds value

max = n1; //use mix variable that holds value

if (n2 > max) max = n2;//use if to compare value and hols value in max variable

if (n3 > max) max = n3;//use if to compare value and hols value in max variable

if (n2 < min) min = n2;//use if to compare value and hols value in min variable

if (n3 < min) min = n3;//use if to compare value and hols value in min variable

m = (n1 + n2 + n3) - (min + max);//defining m variable that arrange value

System.out.println("Ascending: " + min + " " + m + " " + max);//print Ascending order value

System.out.println("Descending: " + max + " " + m + " " + min);//print Descending order value

}

Output:

Enter an integer: 8

And another: 9

And just one more: 7

Ascending: 7 8 9

Descending: 9 8 7

Explanation:

In this program inside the main method three integer variable "n1,n2, and n3" is declared that inputs value from the user end and also defines three variable "min, max, and m" that uses the conditional statement that checks inputs value and assigns value according to the ascending and descending order and prints its values.

5 0

3 years ago

Which of the following is true about advertisements?

katrin [286]

the answer is they often contain biases :)

3 0

2 years ago

[1] Please find all the candidate keys and the primary key (or composite primary key) Candidate Key: _______________________ Pri

AVprozaik [17]

Answer:

Check the explanation

Explanation:

1. The atomic attributes can't be a primary key because the values in the respective attributes should be unique.

So, the size of the primary key should be more than one.

In order to find the candidate key, let the functional dependencies be obtained.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing -> Emp_ID

Course_ID -> Course Name

Course_Name -> Course_ID

Date_Completed -> Course_Name

Closure of attribute { Emp_ID, Date_Completed } is { Emp_ID, Date_Completed , Name, DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Name , Date_Completed } is { Name, Date_Completed , Emp_ID , DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { DeptID, Date_Completed } is { DeptID, Date_Completed , Emp_ID,, Name, , Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Marketing, Date_Completed } is { Marketing, Date_Completed , Emp_ID,, Name, DeptID , Salary, Course_Name, Course_ID}.

So, the candidate keys are :

{ Emp_ID, Date_Completed }

{ Name , Date_Completed }

{ DeptID, Date_Completed }

{ Marketing, Date_Completed }

Only one candidate key can be a primary key.

So, the primary key chosen be { Emp_ID, Date_Completed }..

2.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing -> Emp_ID

Course_ID -> Course Name

Course_Name -> Course_ID

Date_Completed -> Course_Name

3.

For a relation to be in 2NF, there should be no partial dependencies in the set of functional dependencies.

The first F.D. is

Emp_ID -> Name, DeptID, Marketing, Salary

Here, Emp_ID -> Salary ( decomposition rule ). So, a prime key determining a non-prime key is a partial dependency.

So, a separate table should be made for Emp_ID -> Salary.

The tables are R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

and R2( Emp_ID , Salary)

The following dependencies violate partial dependency as a prime attribute -> prime attribute :

Name -> Emp_ID

DeptID -> Emp_ID

Marketing -> Emp_ID

The following dependencies violate partial dependency as a non-prime attribute -> non-prime attribute :

Course_ID -> Course Name

Course_Name -> Course_ID

So, no separate tables should be made.

The functional dependency Date_Completed -> Course_Name has a partial dependency as a prime attribute determines a non-prime attribute.

So, a separate table is made.

The final relational schemas that follows 2NF are :

R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

R2( Emp_ID , Salary)

R3 (Date_Completed, Course_Name, Course_ID)

For a relation to be in 3NF, the functional dependencies should not have any transitive dependencies.

The functional dependencies in R1(Emp_ID, Name, DeptID, Marketing, Date_Completed) is :

Emp_ID -> Name, DeptID, Marketing

This violates the transitive property. So, no table is created.

The functional dependencies in R2 ( Emp_ID , Salary) is :

Emp_ID -> Salary

The functional dependencies in R3 (Date_Completed, Course_Name, Course_ID) are :

Date_Completed -> Course_Name

Course_Name -> Course_ID

Here there is a transitive dependency as a non- prime attribute ( Course_Name ) is determining a non-attribute ( Course_ID ).

So, a separate table is made with the concerned attributes.

The relational schemas which support 3NF re :

R1(Emp_ID, Name, DeptID, Course_ID, Marketing, Date_Completed) with candidate key as Emp_ID.

R2 ( Emp_ID , Salary) with candidate key Emp_ID.

R3 (Date_Completed, Course_Name ) with candidate key Date_Completed.

R4 ( Course_Name, Course_ID ). with candidate keys Course_Name and Course_ID.

6 0

3 years ago

A type of bridge that relies on a curved, semi-circular structure for support

inna [77]

Arch bridges have a semicirclar, curved support.

8 0

3 years ago