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Brut [27]
2 years ago
9

Cheddar cheese costs £7.50 for 1kg Marie buys 200g of cheese How much does she pay

Mathematics
1 answer:
andrew-mc [135]2 years ago
3 0
1kg = 1000g
1000 divided by 5 = 200
7.50 divided by 5 = 1.5
= £1.50
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Six balls are selected at random without replacement from an urn containing three white balls and five blue balls. find the prob
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<span>25/28 is the probability of picking two or three white balls. Given that there are only 8 balls in total and of those 8, 5 of them are blue, this problem can be turned around to "What's the probability of selecting 5 blue balls?" And then subtracting that result from 1. There are a total of 6 ways of selecting all 5 blue balls. The only difference is when the single white ball is selected. The 6 ways are BBBBBW, BBBBWB, ..., WBBBBB. So let's calculate the probability of each of those 6. 5/8 * 4/7 * 3/6 * 2/5 * 1/4 * 3/3 + 5/8 * 4/7 * 3/6 * 2/5 * 3/4 * 1/3 + 5/8 * 4/7 * 3/6 * 3/5 * 2/4 * 1/3 + 5/8 * 4/7 * 3/6 * 3/5 * 2/4 * 1/3 + 5/8 * 3/7 * 4/6 * 3/5 * 2/4 * 1/3 + 3/8 * 5/7 * 4/6 * 3/5 * 2/4 * 1/3 = ? If you look closely at each of the 6 lines, you'll realize that the numerator will always be the product of 5!3 and the denominator will be 3*4*5*6*7*8. So, let's simplify to 6*5!3/(3*4*5*6*7*8) = 6*5*4*3*2*3/(3*4*5*6*7*8) = 2*3/(7*8) = 3/(7*4) = 3/28 Now we just need to calculate 1 - 3/28 = 28/28 - 3/28 = 25/28</span>
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3 years ago
Find the hupotenuse if the legs are 3 and 4
natita [175]

Answer:

None of these

Step-by-step explanation:

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Question 4 of 17
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Javon spent %687 on pokemon cards. Energy cards cost $6 and dragon cards cost $5. If he bought a total of 127 packs then how man
pshichka [43]

Answer:

Javon purchase Energy cards = 52

Javon purchase Dragon cards = 75

Step-by-step explanation:

Given - Javon spent $687 on pokemon cards. Energy cards cost $6

             and dragon cards cost $5.

To find - If he bought a total of 127 packs then how many of each did he buy ?

Proof -

Let Javon purchase Energy cards = x

     Javon purchase Dragon cards = y

Now,

Given that he bought a total of 127 packs

⇒x + y = 127

Also,

Cost for 1 Energy card = $6

⇒Cost of x Energy cards = $ 6x

And

Cost of 1 Dragon card = $5

⇒Cost of y Dragon card = $ 5y

Now,

Given that Javon spent $687 on pokemon cards.

⇒6x + 5y = 687

∴ we get

x + y = 127                                 ..................(1)

6x + 5y = 687                            .................(2)

Multiply by 6 in equation (1) , we get

6(x + y) = 6(127)

⇒6x + 6y = 762                          .................(3)

Now,

Subtract equation (2) from equation (1) , we get

6x + 6y - (6x + 5y )= 762 - 687

⇒6x + 6y - 6x - 5y = 75

⇒y = 75

Now,

Put the value of y in equation (1), we get

x + 75 = 127

⇒x = 127 - 75

⇒x = 52

∴ we get

Javon purchase Energy cards = x = 52

Javon purchase Dragon cards = y = 75

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