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Stells [14]
3 years ago
13

Find the distance between the following points (8 , -5) and (2, 13)

Mathematics
1 answer:
Kryger [21]3 years ago
6 0

Answer:

18.7

Step-by-step explanation:

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Evaluate the expression begin expression . . . 2 times n, times, the quantity n minus 1 . . . end expression, when n = 3 . A 11
arsen [322]

Answer:

B (12)

Step-by-step explanation:

The expression can be written as the following:

(2n)(n-1)

Let n=3

(2*3)(3-1)=(6)(2)=12

So the answer is B (12).

6 0
3 years ago
Help please ASAP. Correct answer will get brainly
djverab [1.8K]

Answer:

I think it's 3,6.....................

4 0
2 years ago
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Solve for x in the equation x2 - 12x+ 36 = 90
12345 [234]

Answer:

6 + 3\sqrt{10\\} or 6 - 3\sqrt{10\\}

Step-by-step explanation:

x^2 - 12x + 36 = 90

x^2 - 12x - 54 = 0

x = \frac{-b +/- \sqrt{b^{2} + 4ac }}{2a}

a = 1, b= -12, c= -54

6 + 3\sqrt{10\\} or 6 - 3\sqrt{10\\}

6 0
3 years ago
8 ten thousands 4 hundreds rename
jeka94
The answer is 80,400
5 0
3 years ago
Megan has $15,000 to invest. She is considering two investment options. Option A pays 3.2% simple interest. Option B pays 4.1% i
True [87]

wheee



Compute each option


option A: simple interest


simple interest is easy

A=I+P

A=Final amount

I=interest

P=principal (amount initially put in)


and I=PRT

P=principal

R=rate in decimal

T=time in years


so given

P=15000

R=3.2% or 0.032 in deecimal form

T=10


A=I+P

A=PRT+P

A=(15000)(0.032)(10)+15000

A=4800+15000

A=19800

Simple interst pays $19,800 in 10 years




Option B: compound interest

for interest compounded yearly, the formula is

A=P(1+r)^t

where A=final amount

P=principal

r=rate in decimal form

t=time in years


given

P=15000

r=4.1% or 0.041

t=10


A=15000(1+0.041)^{10}

A=15000(1.041)^{10}

use your calculator

A=22418.0872024

so after 10 years, she will have $22,418.09 in the compounded interest account





in 10 years, the investment in the simple interest account will be worth $19,800 and the investment in the compounded interest account will be worth$22,418.09

4 0
3 years ago
Read 2 more answers
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