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Nikitich [7]
2 years ago
7

Condense the expression to the logarithm of a single quantity.

Mathematics
1 answer:
kherson [118]2 years ago
3 0

\dfrac 12 \log_3 x - 2\log_3 (y +8)\\ \\=\log_3 x^{\tfrac 12}- \log_3(y+8)^2~~~~~~~~~~~~~~~~~~;[\log_b m^n = n \log_b m]\\\\=\log_3 \left( \dfrac {x^{\tfrac 12}}{y+8)^2} \right)~~~~~~~~~~~~~~~~~~~~~~~~;\left[\log_b \left( \dfrac mn \right) = \log_b m - \log_b n \right]

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Find the midpoint of the line segment joining the points (-2, -1) and (-8,12).
SCORPION-xisa [38]

x¹ = -2 x² = -8

y¹ = -1 y² = 12

Using midpoint formula,

M = ( x¹ + x²/2 ,y¹ + ý²/2)

or,M ={ -2+(-8)/2 , (-1) +12/2}

or, =( -10/2 , 11/2)

:M = ( -5 , 11/2)

6 0
3 years ago
What is the value of b in the equation 3b + 2(b − 1) = 8?
Ray Of Light [21]
<span>3b + 2(b − 1) = 8
3b + 2b - 2 = 8
5b = 10
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answer b = 2</span>
7 0
3 years ago
Read 2 more answers
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Answer:

Step-by-step explanation:

20/6 - 4/6= 16/6= 2 4/6= 2 2/3

7 0
3 years ago
Which of the following is the value of 3x’ – x+2 when x=-4
Aleks [24]

Answer:

-6

Step-by-step explanation:

3x-x+2

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Hope this helps!

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6 0
3 years ago
If f(x)= -4x + 3 and g(x) = 3x² + 2x - 4 find (f+g)(x)
pychu [463]

Answer:

A

Step-by-step explanation:

We have the two functions:

f(x)=-4x+3\text{ and } g(x)=3x^2+2x-4

And we want to find (f+g)(x).

Note that this is the same thing to f(x)+g(x). Therefore:

\begin{aligned} (f+g)(x)&=f(x)+g(x) \\ &=(-4x+3)+(3x^2+2x-4) \end{aligned}

We simply substituted them for their equations.

Simplify. Combine like terms:

=(3x^2)+(-4x+2x)+(3-4)

Add:

=3x^2-2x-1

Hence, our answer is A.

3 0
2 years ago
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