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Andre45 [30]
3 years ago
14

Which quadratic equation defines the function that has zeros at −1/12 and 1/4

Mathematics
1 answer:
erastova [34]3 years ago
5 0
\bf \begin{cases}
x=-\cfrac{1}{12}\implies 12x=-1\implies &12x+1=0\\\\
x=\cfrac{1}{4}\implies 4x=1\implies &4x-1=0
\end{cases}\\\\
-----------------------------

\bf (12x+1)(4x-1)=\stackrel{original~polynomial}{0}\implies \stackrel{FOIL}{48x^2-8x-1=y}
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Remember that if f and g are functions with g(x)\neq 0 then, \frac{d}{dx}\frac{f(x)}{g(x)}=\frac{f'(x)g(x)-g'(x)f(x)}{g(x)^2}.

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