4 years ago

Consider the function f(x)=5x+7.

Mathematics

1 answer:

Brums [2.3K]4 years ago

5 0

you need to clarify. what do you want me to consider? because otherwise I considered it

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3 years ago

Prove whether the quadrilateral is a parallelogram using the Distance & Slope Formulas D(-5, -6), E(5, 2), F(4, -4), G(-6, -

amm1812

Answer:

See the distances bellow

Step-by-step explanation:

Given data

D(-5, -6), E(5, 2)

substitute into the expression for the distance

$d= \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\\\\d= \sqrt((5+5)^2 + (2+6)^2)\\\\d= \sqrt((10)^2 + (8)^2)\\\\d= \sqrt(100 +64)\\\\d= \sqrt((164)\\\\d= 12.80$

E(5, 2), F(4, -4)

$d= \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\\\\d= \sqrt((4-5)^2 + (-4-2)^2)\\\\d= \sqrt((-1)^2 + (-6)^2)\\\\d= \sqrt(1+36)\\\\d= \sqrt((37)\\\\d= 6.08$

F(4, -4), G(-6, -12)

$d= \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\\\\d= \sqrt((-6-4)^2 + (-12+4)^2)\\\\d= \sqrt((-10)^2 + (-8)^2)\\\\d= \sqrt(100+64)\\\\d= \sqrt((164)\\\\d= 12.80$

G(-6, -12), D(-5, -6)

$d= \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\\\\d= \sqrt((-6+5)^2 + (-12+6)^2)\\\\d= \sqrt((-1)^2 + (-6)^2)\\\\d= \sqrt(1+36)\\\\d= \sqrt((37)\\\\d= 6.08$