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____ [38]
3 years ago
14

Sam and Bobby want to know who cycled faster. The table shows the total miles Sam traveled over time. The graph shows the same r

elationship for Bobby. Who cycled faster.
Find the unit rate for Sam
Find the unit rate for Bobby
The unit rate is
Who cycled faster

Mathematics
1 answer:
tigry1 [53]3 years ago
7 0

Answer:

<h2>Sam cycled fast, at a rate of 10 miles per hour.</h2>

Step-by-step explanation:

To solve this problem we have to find the slope of each case. The definition of a slope is:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\

Where (x_{1};y_{1}) is the first point, and (x_{2};y_{2}) is the second point.

Let's find each slope.

<h3>Sam.</h3>

Let's use the points (2;20) and (5;50)

Applying the definition of the slope, we have:

m_{sam} =\frac{50-20}{5-2}=\frac{30 \ miles}{3 \ hour}=10 \ miles/hour

This relation means that Sam cycled 10 miles per hour.

<h3>Bobby.</h3>

Let's use the points (2;18) and (6;54)

m=\frac{54-18}{6-2}=\frac{36 \ miles}{4 \ hour}=9 \ miles/hour

Bobby cycled 9 miles per hour.

Therefore, according to these ratios, Sam cycled fast, at a rate of 10 miles per hour.

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Step-by-step explanation:

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EG:

1) the amount of numbers between 5 and 10, including 5

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3 years ago
Given that <br> a:b = 4:5 <br> and <br> b:c=3.2 <br> find the ratio a:b:c in its simplest form
alex41 [277]
A:b = 4:5
b:c=3:2
b was 5 then it was 3, so you have to find the common multiple which is 15.
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you’d have to times the 2 (c) by 5 since 5x3 is 15 again.
therefore the answer would be
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3 years ago
Read 2 more answers
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Sedbober [7]
First to get the equation you knew to understand one thing about perpendicular lines. The slope of the line is the opposite reciprocal of the perpendicular lines or the new slope is m = 10.

Then you use the formula
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you plug in your values from the point and the new slope.
(1,5) with new slope m
5= 10(1)+b
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3 years ago
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tensa zangetsu [6.8K]

Answer:

Step-by-step explanation:

35% means 35 per hundred. 35/100. simplify and write as 7/20.

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Eva8 [605]

Answer:

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under a reflection in the x- axis

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