5y+2(3y-1)=__y-(y+2)
5y+6y-2=__y-y-2
11y-2+2+y=__y
12y=___y
so 12
Well, the number is more than 8, but less than 9, so it must be between 8 and 9
Answer:
(5, -1)
Step-by-step explanation:
Add the x-coordinates and divide by 2.
Add the y-coordinates and divide by 2.
x-coordinate of midpoint: (2 + 8)/2 = 10/2 = 5
y-coordinate of midpoint: (-5 + 3)/2 = -2/2 = -1
Midpoint: (5, -1)
