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Dominik [7]
3 years ago
8

At school there are 526 students and 263 are girls about how likely is it that a randomly chosen student will be a boy

Mathematics
2 answers:
max2010maxim [7]3 years ago
3 0

Answer: 50% chance that a randomly chosen student will be a boy

denis-greek [22]3 years ago
3 0

Answer:

Step-by-step explanation

total number of student= 526

total number of girl= 263

total number of boy= 526 - 263 = 263

Probability that chosen student will be boy = number of favorable items/ total number of possible outcome= 263/526 = 1/2

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A mixture of compounds X and Y in a 0.100-cm cell had an absorbance of 0.215 at 272 nm and 0.191 at 327 nm. Find [X] and [Y] in
Oksi-84 [34.3K]

Answer: The concentration of X is 7.13582\times 10^{-6} and the concentration of Y is 2.53159\times 10^{-5}.

Step-by-step explanation:

Since we have given that

At 272 nm, absorbance = 0.215

At 327 nm, absorbance = 0.191

As we have given that

                               Compound X             Compound Y

272                               16400                            3870

327                                3990                             6420

So, our equations becomes

16400C_1+3870c_2=0.215\\\\3990C_1+6420C_2=0.191

By solving these two equations, we get that

C_1=7.13582\times 10^{-6}\\\\C_2=2.53159\times 10^{-5}

Hence, the concentration of X is 7.13582\times 10^{-6} and the concentration of Y is 2.53159\times 10^{-5}.

5 0
3 years ago
Which of the following can be used to calculate the volume of water inside the fish bowl?
Lunna [17]

The volume of a sphere can be calculated as

V=\frac{4}{3}\pi r^3

Where r is the radius of the sphere

We want to calculate half of the volume, then we must divide that volume by 2

V^{\prime}=\frac{1}{2}\frac{4}{3}\pi r^3

Now we must find the radius of our sphere, the segment AB is the diameter of the sphere, and the radius is half od the diameter, then

r=\frac{AB}{2}=\frac{12}{2}=6

Let's put it into our equation

\begin{gathered} V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)(\pi)(r)^3 \\  \\ V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)(\pi)(6)^3 \end{gathered}

The problem says to use

\pi\approx\frac{22}{7}

Then

V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)\left(\frac{22}{7}\right)(6)^3

Final answer:

The formula that can be used to calculate the volume of water inside the fish bowl is

V=\frac{1}{2}\left(\frac{4}{3}\right)\left(\frac{22}{7}\right)(6)^3

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1 year ago
Which situation can be represented by 3s = 5s - 6 ?
grin007 [14]

Answer:

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Step-by-step explanation:

3s=5s-6

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