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love history [14]
3 years ago
15

L 4.6.3 Test (CST): Linear Equations Use the coordinates of the labeled point to find a point-slope equation of the line. 16 6 (

-2,-5) -6 A. y- 5 = -2(x - 2) O B. y + 5 = -2(x + 2) O c. y + 5 = 2(x + 2) E PREVIOUS​

Mathematics
1 answer:
nydimaria [60]3 years ago
6 0

Answer:

B.

Step-by-step explanation:

Have a great day!

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Please help me!!!!!!!
GrogVix [38]
4x^2 - 30 = 34
4x^2 = 34 + 30
4x^2 = 64
x^2 = 64/4
x^2 = 16
x = sqrt 16
x = -4 and 4......E and F

5 0
4 years ago
Determine which polynomial is a perfect square trinomial.
Colt1911 [192]
 <span>Trinomial Ax^2 + Bx + C is perfect square if: 
A > 0 
C > 0 
B = ±2√A√C 

36b^2 − 24b − 16
 C < 0 

4a^2 − 10a + 25
 2√A√C = 2*2*5 = 20,
 B = −10 

16x^2 + 24x − 9
 not perfect square,
 C < 0 

4x^2 − 12x + 9
perfect square:
A>0,
C>0,
2√A√C
= 2*2*3
= 12
 = -B 
= (2x − 3)^2
hope this helps</span>
6 0
3 years ago
Read 2 more answers
Isabella tossed a coin and spun a spinner that is divided into 3 equal sections. She did this 50 times. The results are shown in
Hatshy [7]

Answer:

ur gay landen

Step-by-step explanation:

4 0
3 years ago
Please show working out
alekssr [168]

Answer:

x= 14.84cm

Step-by-step explanation:

cos(52)=x/28

cos(52)*28=x

x=14.84 cm

7 0
4 years ago
Read 2 more answers
Show that if u+v and u-v are orthognal, then the vectors u and v must have the same length.
pashok25 [27]

Answer with Step-by-step explanation:

We are given that

u+ v and u-v are orthogonal

We have to prove that u and v must have the same length.

When two vector a and b are orthogonal then

a\cdot b=0

By using the property

(u+v)\cdot (u-v)=0

We know that

(a+b)\cdot (a-b)=\mid a\mid^2-\mid b\mid^2

\mid u\mid ^2-\mid v\mid^2=0

\mid u\mid^2=\mid v\mid^2

Magnitude is always positive

When power of base on both sides are equal then base will be equal

Therefore,

\mid u\mid=\mid v\mid

Hence, the length of vectors u and v must have the same length.

5 0
4 years ago
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