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Naddik [55]
3 years ago
7

Which relationship describes angles 1 and 2?

Mathematics
2 answers:
galina1969 [7]3 years ago
8 0
Angle 1 and 2 are vertical angles

Hope this helps :)
dezoksy [38]3 years ago
4 0
Hi there! The answer is complementary angles.

The angle between line 1 and 2 is 90° and this is called a complementary angle.
You might be interested in
Suppose that you have $6000 to invest. Which investment yields the greater return over four years: 8.25% compounded quarterly or
WARRIOR [948]
\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.25\%\to \frac{8.25}{100}\to &0.0825\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.0825}{4}\right)^{4\cdot 4}\implies A=6000(1.020625)^{16}\\\\
-------------------------------\\\\



\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.3\%\to \frac{8.3}{100}\to &0.083\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semiannually, thus two}
\end{array}\to &2\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.083}{2}\right)^{2\cdot 4}\implies A=6000(1.0415)^8

compare them away.
4 0
3 years ago
Find the surface area of the triangular prism. *
jekas [21]

Answer:

1032 yds

Step-by-step explanation:

Al =(a+b+c)h

5 0
4 years ago
Find the value of x..........
Leviafan [203]

Answer:

x = 53.5

Step-by-step explanation:

x is one half the difference of the intercepted arcs, that is

x = 0.5(137 - 30) = 0.5 × 107 = 53.5

8 0
3 years ago
[20 Points] I need help with these questions:
I am Lyosha [343]

Slope-intercept form:

y = mx + b

"m" is the slope, "b" is the y-intercept (the y value when x = 0)

You need to find "m" and "b"


1.) For lines to be perpendicular, their slopes have to be the opposite/negative reciprocal (flipped sign and number)

For example:

slope is 2

perpendicular line's slope is -1/2

slope is -2/3

perpendicular line's slope is 3/2


The given line's slope is -4, so the perpendicular line's slope is 1/4.

y = 1/4x + b

To find "b", you can plug in the point (4, -2) into the equation

y = 1/4x + b

-2 = 1/4(4) + b

-2 = 1 + b

-3 = b


y=\frac{1}{4} x-3


2.) To find "m", use the slope formula and plug in the two points:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m=\frac{8-(-1)}{-2-4}

m=\frac{8+1}{-2-4}

m=\frac{9}{-6} =-\frac{3}{2}


y = -3/2x + b

Plug in one of the points to find "b"

y = -3/2x + b

-1 = -3/2(4) + b

-1 = -6 + b

5 = b


y=-\frac{3}{2}x +5


3.) y-intercept: 5 (since the given equation's y-intercept is 5)

I'm confused with what they mean by "steep", so I'll try to update this later unless someone else has an answer


So I looked it up, and it says that a steep slope is a line that is more vertical [if that makes sense]. So you could do a slope of +3 (more than 3, like 4, 5, 6...) because the given line's slope is 3, and you need a new line that is more steeper(vertical)

3 0
4 years ago
Rectangle J'K'L'M' shown on the grid is the image of rectangle JKLM after transformation. The same transformation will be applie
adoni [48]

Answer:

Location of T' on the coordinate axis will be (16,7).

T (6,4) → T' (16,7).

Step-by-step explanation:

coordinate vertices of points in rectangle JKLM are:

J (-8,-8)

K (-4,-8)

L (-4,-5)

M (-8,-5)

and coordinate vertices of points in rectangle J'K'L'M' are:

J' (2,-5)

K' (6,-5)

L' (6,-2)

M' (2,-2)

coordinate vertices of points in Quadrilateral STUV are:

S (1,4)

T (6,4)

U (4,6)

V (2,6)


transformation in coordinate vertices from rectangle JKLM to rectangle J'K'L'M' is:

J (-8,-8) → J' (2,-5)

⇒ along x axis -8 → 2 which means that rectangle is shifting towards right by 10 units.

and along y axis -8 → -5 which means that the rectangle is shifting upwards by 3 units.

similarly for

K (-4,-8) → K' (6,-5)

⇒ along x axis -4 → 6 which means that rectangle is shifting towards right by 10 units.

and along y axis -8 → -5 which means that the rectangle is shifting upwards by 3 units.

L (-4,-5) → L' (6,-2)

⇒ along x axis -4 → 6 which means that rectangle is shifting towards right by 10 units.

and along y axis -5 → -2 which means that the rectangle is shifting upwards by 3 units.

M (-8,-5) → M' (2,-2)

⇒ along x axis -8 → 2 which means that rectangle is shifting towards right by 10 units.

and along y axis -5 → -2 which means that the rectangle is shifting upwards by 3 units.


So, the location of T' of the Quadrilateral S'T'U'V' on the coordinate plane will be:

along x axis the Quadrilateral will shift towards right by 10 units

So, 6 → 6+10=16

and along y axis the Quadrilateral will shift upwards by 3 units

So, 4 → 4+3=7

⇒ T (6,4) → T' (16,7).

7 0
3 years ago
Read 2 more answers
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