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Rainbow [258]
3 years ago
13

The wholesale price for a shirt is $5.50. A certain department store marks up the wholesale price by 40%. Find the price of the

shirt in the department store.
Mathematics
1 answer:
Kazeer [188]3 years ago
7 0

Answer:

$7.7

Step-by-step explanation:

Hello, I can help you with this

you can solve this by using a simple rule of three.

Step 1

define

if the wholesale price for a shirt is $5.50,it is 100 percent

$5.50⇔100%

the new price(x) is 40% more than the original, it means 140%

x  ⇔ 140%

the relation is

\frac{5.5}{100}= \frac{x}{140}\\

Step 2

solve for x(isolate x)

\frac{5.5}{100}= \frac{x}{140}\\x=\frac{5.5*140}{100}\\x=7.7

the price of the shirt in the department store is $7.7

Have a nice day.

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Subtract 1/2 × (equation 1) from equation 3:

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{6 x - 2 y + z = 16 | (equation 1)

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Swap equation 2 with equation 3:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+8 y + 5 z = 56 | (equation 3)

Subtract 4/5 × (equation 2) from equation 3:

{6 x - 2 y + z = 16 | (equation 1)

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0 x+0 y+(13 z)/5 = 24 | (equation 3)

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{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

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Divide equation 3 by 13:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Subtract 3 × (equation 3) from equation 2:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y+0 z = 160/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Divide equation 2 by 10:

{6 x - 2 y + z = 16 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Add 2 × (equation 2) to equation 1:

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0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Subtract equation 3 from equation 1:

{6 x+0 y+0 z = 120/13 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Divide equation 1 by 6:

{x+0 y+0 z = 20/13 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Collect results:

Answer:  {x = 20/13 , y = 16/13 , z = 120/13

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