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KengaRu [80]
2 years ago
13

Slove the inequality for n 24 > 18 + 2n

Mathematics
2 answers:
S_A_V [24]2 years ago
7 0

Answer:

3 > n

Step-by-step explanation:

24 > 18 + 2n (minus 18 from both sides)

6 > 2n (divide by 3 in both sides)

3 > n

vodka [1.7K]2 years ago
3 0

Answer:

n  <  3

Step-by-step explanation:

n can be any number greater than 3. It can e 4 or more....4+

4, 5, 6, 7, 8, 9, 20, 100, 10,000,000,000

ANY NUMBERS GREATER THAN 3

How do I know?

Well we can solve this like it was an equation

24 > 18 + 2n

Subtract 18 on both sides

24 - 18 > 18 - 18 + 2n

6  >  2n

Now divide by 2 on both sides to isolate the variable "n"

6/2 > 2n/2

3 > n

Hope this helped!

Have a supercalifragilisticexpialidocious day!

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Company XYZ has 34 employees in the Finance Department, 45 technicians, and 32 in the Engineering Department. The HR Department
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Answer:

66.7%

Step-by-step explanation:

The total number of complaints were:

5 + 3 + 7 = 15

The percent that came from either technicians or the Finance Department is:

(5 + 3) / 15 × 100% = 66.7%

7 0
2 years ago
The amount of syrup that people put on their pancakes is normally distributed with mean 63 mL and standard deviation 13 mL. Supp
andreyandreev [35.5K]

Answer:

(a) X ~ N(\mu=63, \sigma^{2} = 13^{2}).

    \bar X ~ N(\mu=63,s^{2} = (\frac{13}{\sqrt{43} } )^{2}).

(b) If a single randomly selected individual is observed, the probability that this person consumes is between 61.4 mL and 62.8 mL is 0.0398.

(c) For the group of 43 pancake eaters, the probability that the average amount of syrup is between 61.4 mL and 62.8 mL is 0.2512.

(d) Yes, for part (d), the assumption that the distribution is normally distributed necessary.

Step-by-step explanation:

We are given that the amount of syrup that people put on their pancakes is normally distributed with mean 63 mL and a standard deviation of 13 mL.

Suppose that 43 randomly selected people are observed pouring syrup on their pancakes.

(a) Let X = <u><em>amount of syrup that people put on their pancakes</em></u>

The z-score probability distribution for the normal distribution is given by;

                      Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = mean amount of syrup = 63 mL

            \sigma = standard deviation = 13 mL

So, the distribution of X ~ N(\mu=63, \sigma^{2} = 13^{2}).

Let \bar X = <u><em>sample mean amount of syrup that people put on their pancakes</em></u>

The z-score probability distribution for the sample mean is given by;

                      Z  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = mean amount of syrup = 63 mL

            \sigma = standard deviation = 13 mL

            n = sample of people = 43

So, the distribution of \bar X ~ N(\mu=63,s^{2} = (\frac{13}{\sqrt{43} } )^{2}).

(b) If a single randomly selected individual is observed, the probability that this person consumes is between 61.4 mL and 62.8 mL is given by = P(61.4 mL < X < 62.8 mL)

   P(61.4 mL < X < 62.8 mL) = P(X < 62.8 mL) - P(X \leq 61.4 mL)

  P(X < 62.8 mL) = P( \frac{X-\mu}{\sigma} < \frac{62.8-63}{13} ) = P(Z < -0.02) = 1 - P(Z \leq 0.02)

                                                           = 1 - 0.50798 = 0.49202

  P(X \leq 61.4 mL) = P( \frac{X-\mu}{\sigma} \leq \frac{61.4-63}{13} ) = P(Z \leq -0.12) = 1 - P(Z < 0.12)

                                                           = 1 - 0.54776 = 0.45224

Therefore, P(61.4 mL < X < 62.8 mL) = 0.49202 - 0.45224 = 0.0398.

(c) For the group of 43 pancake eaters, the probability that the average amount of syrup is between 61.4 mL and 62.8 mL is given by = P(61.4 mL < \bar X < 62.8 mL)

   P(61.4 mL < \bar X < 62.8 mL) = P(\bar X < 62.8 mL) - P(\bar X \leq 61.4 mL)

  P(\bar X < 62.8 mL) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{62.8-63}{\frac{13}{\sqrt{43} } } ) = P(Z < -0.10) = 1 - P(Z \leq 0.10)

                                                           = 1 - 0.53983 = 0.46017

  P(\bar X \leq 61.4 mL) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } \leq \frac{61.4-63}{\frac{13}{\sqrt{43} } } ) = P(Z \leq -0.81) = 1 - P(Z < 0.81)

                                                           = 1 - 0.79103 = 0.20897

Therefore, P(61.4 mL < X < 62.8 mL) = 0.46017 - 0.20897 = 0.2512.

(d) Yes, for part (d), the assumption that the distribution is normally distributed necessary.

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3 years ago
What is √75 in simplified form? A 5√3 B 25√3 C √5 D 3√25 Answer Fast For 30 Points!
Kaylis [27]

The answer is A. 5√3

6 0
2 years ago
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How does solving the equation arithmetically compare to solving an equation algebraically
IRISSAK [1]
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By noon, the temperature increased 21 from the morning low -13 what was was the tempature noon
torisob [31]
-13+21=14
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