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KengaRu [80]
2 years ago
13

Slove the inequality for n 24 > 18 + 2n

Mathematics
2 answers:
S_A_V [24]2 years ago
7 0

Answer:

3 > n

Step-by-step explanation:

24 > 18 + 2n (minus 18 from both sides)

6 > 2n (divide by 3 in both sides)

3 > n

vodka [1.7K]2 years ago
3 0

Answer:

n  <  3

Step-by-step explanation:

n can be any number greater than 3. It can e 4 or more....4+

4, 5, 6, 7, 8, 9, 20, 100, 10,000,000,000

ANY NUMBERS GREATER THAN 3

How do I know?

Well we can solve this like it was an equation

24 > 18 + 2n

Subtract 18 on both sides

24 - 18 > 18 - 18 + 2n

6  >  2n

Now divide by 2 on both sides to isolate the variable "n"

6/2 > 2n/2

3 > n

Hope this helped!

Have a supercalifragilisticexpialidocious day!

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jeka94

Answer:

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Step-by-step explanation:

1) replace the x with 7

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7 0
3 years ago
Can somebody please show me how to do this problem
tia_tia [17]

Answer:

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Step-by-step explanation:

As with most graphing problems not involving straight lines, it works well to start with a table of values. Pick a few values of x and compute f(x) and g(x) for those values. Plot the points and draw a smooth curve through them.

As in the attached, your table will show that there are two points of intersection between f(x) and g(x), and that for values of x more than 4, g(x) becomes much greater very quickly. Both curves rapidly reach the top of your graph space.

To find whether f(20) or g(20) is greater, you can evaluate the functions for that value of x.

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3 years ago
I need help finishing a question. I used the explanation function on the program, but it didn't specify what to do to get the fi
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I would compute sqrt(1 + 160pi^2) first to get approximately 39.75093337

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In short, I computed \frac{1+\sqrt{1+160\pi^2}}{2\pi} only focusing on the plus for now.

----------------------

If you were to compute \frac{1-\sqrt{1+160\pi^2}}{2\pi} you should get roughly -6.167402596 as your other solution. Each solution can then be plugged into the original equation to check if you get 0 or not. You likely won't land exactly on 0 but you'll get close enough.

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Answer:

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Step-by-step explanation:

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Answer:

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