Answer:
D) ± .0207
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
The width of the interval is given by the following formula:
In a random sample of 810 women employees, it is found that 81 would prefer working for a female boss.
This means that
95% confidence level
So , z is the value of Z that has a pvalue of
, so
.
The width of the 95% confidence interval for the proportion of women who prefer a female boss is
So the correct answer is:
D) ± .0207
