Hello!
x² - 4x + 6 = 9 <=>
<=> x² - 4x + 6 - 9 = 0 <=>
<=> x² - 4x - 3 = 0 <=>
<=> x = -(-4)±√(-4)²-4×1×(-3)/2×1 <=>
<=> x = 4±√16+12/2 <=>
<=> x = 4±√28/2 <=>
<=> x = 4±2√7/2 =>
=> x = 4+2√7/2 and x = 4-2√7/2 =>
=> x = 2+√7 and x = 2-√7
The equation has two solutions.
Good luck! :)
We are asked for the number of <span>six-digit odd numbers that can be formed. the left-most digit should not be zero because it make the number -five digit already. An odd number ends only in 1, 3, 5, 7 and 9. Using counting, the 6th digit can only have 5 numbers, the 5th, 4th, 3rd, and 2nd can have, 10 numbers. The first number can only have 9 numbers. Hence the total number is 450,000</span>
Answer:
6.384 rounded to one decimal place is 6.4
Step-by-step explanation:
Answer:
5 steps.
Step-by-step explanation:
- Recieving
- Understanding
- Evaluating
- Remembering
- Responding
hope it helps!
When
, you have
Now assume this is true for
, i.e.
and under this hypothesis show that it's also true for
. You have
In other words, there exists
such that
Rewriting, you have
and this is equivalent to
modulo 9, as desired.
