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3 years ago

Can I Get Help On This Question?

Mathematics

1 answer:

Gnoma [55]3 years ago

3 0

I believe it would just be -1

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Answer for brainliest

Misha Larkins [42]

Answer:

Step-by-step explanation:

you just add all the number together

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3 years ago

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For the expression 6x-2y+5

Svetach [21]

Y = 3x - 2.5
You have to get the y by itself.
Subtract 6x to both sides. Then divide by -2.

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4 years ago

Which table is a linear function

dimaraw [331]

Answer:

Step-by-step explanation:

because option a. has two y functions

and option d is the only consistent one and it counts by 8

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4 years ago

What two numbers multiply together to equal -32 and add together to equal positive four

Andru [333]

Because multiply of these two number get you -32, one of these number must be negative.

And because sum of them are positive, positive number must be larger than that negative number (without minus sign)

So list of possible answers are:

-1, 32; -2, 16; -4, 8

And we can see that
-4+8 = 4

So these two numbers are 8 and -4.

7 0

3 years ago

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2 cards are chosen from a deck of cards. The first card is replaced before choosing the second card. What is the probability tha

fgiga [73]

Answer:

The probability that the first card chosen is club and second card chosen is of heart is .

Step-by-step explanation:

Total number of cards in the deck is 52 (total number of cases).

Probability of an event E can be formulated as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

For event A, number of cards of type club = 13 (favorable cases)

So,

$P(A) = \dfrac{13}{52} \\\Rightarrow P(A) = \dfrac{1}{4}$

For event B, number of cards of type heart = 13 (favorable cases)

So,

$P(B) = \dfrac{13}{52} \\\Rightarrow P(B) = \dfrac{1}{4}$

It is given that card is replaced before choosing the second card.

These events A and B are independent events, happening of one event does not effect the happening of other. And probability of both happening together can be found as following:

$P(A \cap B) = P(A) \times P(B)$

$\Rightarrow P(A \cap B) = \dfrac{1}{4} \times \dfrac{1}{4}\\\Rightarrow P(A \cap B) = \dfrac{1}{16}$

The probability that the first card chosen is club and second card chosen is of heart is $\frac{1}{16}$ .

8 0

3 years ago