The answer to the question is 90
Given: y = 2x^2 - 32x + 56
1) y = 2 [ x^2 - 16x] + 56
2) y = 2 [ (x - 8)^2 - 64 ] + 56
3) y = 2 (x - 8)^2 - 128 + 56
4) y = 2 (x - 8)^2 - 72 <----------- answer
Minimum = vertex = (h,k) = (8, - 72)
=> x-ccordinate of the minimum = 8 <-------- answer
Step-by-step explanation:
the answe to dis question is 2
Answer:
16
Step-by-step explanation:
Answer:
x = 3
Step-by-step explanation:
3 ( x + 1 ) = 5 ( x- 2 ) + 7
Expand
3 x + 3 = 5 x - 10 + 7
Minus 5 x from both sides
- 2 x + 3 = - 10 + 7
Minus 3 from both sides
- 2 x = - 10 + 4
Simplify
- 2 x = - 6
Divide both sides by - 2
x = 3
