Find three consecutive odd integers such that the sum of the largest and twice the smallest is 25. If x represents the smallest
integer, then which equation could be used to solve the problem? 2x + x + 2 = 25 2x + x + 4 = 25 2x + 2x + 4 = 25
1 answer:
1. x
2. x + 2
3. x + 4
x + 4 + 2x = 25. Second option is the answer.
Combine like terms
3x + 4 = 25
Subtract 4 from both sides
3x = 21
Divide both sides by 3
x = 7
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