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djyliett [7]
3 years ago
10

Find three consecutive odd integers such that the sum of the largest and twice the smallest is 25. If x represents the smallest

integer, then which equation could be used to solve the problem? 2x + x + 2 = 25 2x + x + 4 = 25 2x + 2x + 4 = 25
Mathematics
1 answer:
Murrr4er [49]3 years ago
5 0
1. x
2. x + 2
3. x + 4

x + 4 + 2x = 25. Second option is the answer.


Combine like terms
3x + 4 = 25
Subtract 4 from both sides
3x = 21
Divide both sides by 3
x = 7
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Answer:

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Step-by-step explanation:

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Step: 2 Now the new dividend is -x^4+1 and Divisor is (x+1)  when divided the quotient will be x^4-x^3 and remainder will be x^3+1

Step: 3 Now the new dividend is x^3+1 and Divisor is (x+1)  when divided the quotient will be x^4-x^3+x^2 and remainder will be -x^2+1

Step: 4 Now the new dividend is -x^2+1 and Divisor is (x+1)  when divided the quotient will be x^4-x^3+x^2-x and remainder will be x+1

Step: 5 Now the new dividend is x+1 and Divisor is (x+1)  when divided the quotient will be x^4-x^3+x^2-x+1 and remainder will be 0.

Hence When the polynomial (x^5+1) is divided by  (x+1) the answer or quotient will be equal to  x^4-x^3+x^2-x+1 and remainder will be 0.

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Write the number eighteeb in another way
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