Answer: provided in the explanation segment
Step-by-step explanation:
(a). from the question, we can see that since that б is known, we can use standard normal, z.
we are asked to find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error?
⇒ 80% confidence interval for the average weight of Allen's hummingbirds is given thus;
x ± z * б / √m
which is
3.15 ± 1.28 * 0.32/√10
= 3.15 ± 0.1295 = 3.0205 or 3.2795
(b). normal distribution of weight (c) б is known
(c). option (a) and (e) are correct
(d). from the question, let sample size be given as S
this gives';
1.28 * 0.32/√S = 0.15
√S = (1.28 * 0.32) / 0.15 = 2.73
S = 7.4529
cheers i hope this helps
Use the diamond box method.
x^2 | -6x
10x | -60
-60x^2
10x. -6x
4x
(x-6)(x+10)
x= 6, -10
Answer:
2460
Step-by-step explanation:
Hope this helps :)
Answer:
The driver was traveling at approximately 68.2 miles per hour
Step-by-step explanation:
Recall that one km equals approximately 0.62 miles, therefore, in order to find the speed of the driver in miles per hour, we just need to convert the 110 km into miles.
if one km equals 0.62 miles, then 110 km will equal the product of 110 times 0.62 miles. That is:
110 * 0.62 = 68.2 miles
Then the speed will translate into :
110 km/h = 68.2 mi/h
1/3 are two times in 1/6.
Yes, 1/3 is bigger than 1/6.
