Answer:
12
Step-by-step explanation:
4 • 1/3 = 4/3
9 • 4/3 = 36/3
36/3 simplified is 12
Answer:
The width of the piece of construction paper is 6.75 inches.
Step-by-step explanation:
The area of the paper =
sq inches
The length of the paper =
in
Let the width of the paper = w inches
Now, AREA OF THE PAPER = LENGTH x WIDTH
or, 65.25 sq. inches = 9. 66 in x w in
⇒ 65.25 = 9.66 x w
or, ![w = \frac{65.25}{9.66} \implies w = 6.75](https://tex.z-dn.net/?f=w%20%3D%20%5Cfrac%7B65.25%7D%7B9.66%7D%20%5Cimplies%20w%20%3D%206.75)
or, w = 6. 75 inches
Hence, the width of the piece of construction paper is 6.75 inches.
Division I'm pretty sure Try that
F(g(x)) = x + 1 . Just replace square root of x-2 to x in f(x)