How do you solve for -7.21/-3.5
1 answer:
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Option 1
To find the y-intercept of a quadratic that is in factor formed follow the steps below:
First take the factor form and put it into standard quadratic form
Standard quadratic form:
To put the the factor form of a qudratic into standard form, we use the foil method
(x-6)(x-2) =
Now to find the y-intercept, input 0 where the x is located:
y-intercept = (0,12)
Why did I use 0? Remember the y-intercept is where the line crosses the y axis so this means the x value of the y intercept is always = 0. Also, not, to find the y-intercept, you could of just multiplied the 6 and 2 in the factored form to get the 12 and since you know that the x is always 0 at the y-intercept, you know that the y-intercept is at (0,12)
Option 2
Input 0 for x in f(x) = (x-6)(x-2)
f(x) = (x-6)(x-2)
f(0) = (0 - 6)(0 - 2)
f(0) = (6)(2) = 12
x = 0
f(0) = y = 12
y-intercept = (0,12)
To find the y-intercept of a quadratic that is in factor formed follow the steps below:
First take the factor form and put it into standard quadratic form
Standard quadratic form:
To put the the factor form of a qudratic into standard form, we use the foil method
(x-6)(x-2) =
Now to find the y-intercept, input 0 where the x is located:
y-intercept = (0,12)
Why did I use 0? Remember the y-intercept is where the line crosses the y axis so this means the x value of the y intercept is always = 0. Also, not, to find the y-intercept, you could of just multiplied the 6 and 2 in the factored form to get the 12 and since you know that the x is always 0 at the y-intercept, you know that the y-intercept is at (0,12)
Option 2
Input 0 for x in f(x) = (x-6)(x-2)
f(x) = (x-6)(x-2)
f(0) = (0 - 6)(0 - 2)
f(0) = (6)(2) = 12
x = 0
f(0) = y = 12
y-intercept = (0,12)
