Question

What is the right-hand limit of the function `f(x) = (x^2 + 2x - 3)/(x - 3)` as x approaches 2?

Answer 1

$\displaystyle\\\lim_{x\to 2}\dfrac{x^2+2x-3}{x-3}=\dfrac{2^2+2\cdot2-3}{2-3}=\dfrac{5}{-1}=-5$