Question

Write the equation of the line with a slope of -5 and a y-intercept of (0,3).

Answer 1

Slope between 2 points (x1,y1) and (x2,y2) is (y2-y1)/(x2-x1)

y=mx+b
slope=m
b=y intercept

undifined slope will be x=constant where the costant is the x value in the given point (x,y)


so
first one
slope is -5 y int of 3
y=-5x+3



2nd
slope is -1/3
a point is (6,-4)
subsitute
-4=-1/3(6)+b
-4=-2+b
-2=b

equation is y=-1/3x-2




3rd
slope
betwen (0,-4) and (-2,2) is
(2-(-4))/(-2-0)=(2+4)/(-2)=6/-2=-3
a point, way the y intercept is -4
y=-3x-4



4th
slope beten (-6,1) and (-4,2) is (2-1)/(-4-(-6))=(1)/(-4+6)=1/2
a point is (-6,1)
1=1/2(-6)+b
1=-3+b
4=b
equation is
y=1/2x+4



5th
undifned
x=something
(x,y)
(2,5)
x=2 is da equation