C=λν ==> λ=c/ν
λ= 3x10^8 m/s / 1.50 x 10^15 s^-1
λ= 2 x 10^-7 m
λ= 200 nm
For the answer to the question above, let us assume that all Co2 is given off and this are the mass that is lost:
mass at start = 14.00 = 56.70 = 70.70g
<span>mass at end = 64.96g </span>
<span>mass lost = 5.74g </span>
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</span><span>I hope my answer helped you. Have a nice day!</span>
It attracts other water molecules due to water’s polarity and hydrogen bonding
Answer:
The answer is 3
Explanation:
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Answer:
The Kc of this reaction is 311.97
Explanation:
Step 1: Data given
Kp = 0.174
Temperature = 243 °C
Step 2: The balanced equation
N2(g) + 3H2(g) ⇌ 2NH3(g)
Step 3: Calculate Kc
Kp = Kc *(RT)^Δn
⇒ with Kp = 0.174
⇒ with Kc = TO BE DETERMINED
⇒ with R = the gas constant = 0.08206 Latm/Kmol
⇒ with T = the temperature = 243 °C = 516 K
⇒ with Δn = number of moles products - moles reactants 2 – (1 + 3) = -2
0.174 = Kc (0.08206*516)^-2
Kc = 311.97
The Kc of this reaction is 311.97
