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sleet_krkn [62]
3 years ago
5

The percent yield of this reaction is consistently 92.0%. CH4(g) + 4 S(g) → CS2(g) + 2 H2S(g) How many grams of sulfur would be

needed to obtain 72.57 g of CS2?
Chemistry
1 answer:
dybincka [34]3 years ago
6 0

Answer:

132.17 g

Explanation:

The reaction given , in the question is -

    CH₄ (g ) + 4 S ( g ) ---> CS₂ ( g ) + 2H₂S  ( g )

From the reaction , 4 mole of S is required for the production of 1 mole of  CS₂ .

since ,

Moles of  CS₂  = given mass of CS₂ / Molecular weight  of  CS₂

Since ,

the Molecular weight of  CS₂ = 76

Given ,  mass of CS₂ =  72.57 g

Moles of  CS₂ = 72.57  / 76 = 0.95 mol

Since ,

The yield is 92.0 % .

Moles of S required = 4 * 0.95 mol / 0.92 = 4.13 moles

Mass of S required = 4.13 * 32 = 132.17 g .

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Water(H2O) is composed of the same elements as carbon monoxide (CO). How do their properties compare?
adoni [48]
The correct answer of the given question above would be option B. Water is composed of the same elements as carbon monoxide, but their properties compare because they have different properties due to the different arrangement of atoms. Hope this answer helps.
8 0
3 years ago
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How many points should be plotted when creating a scatterplot from the table of values below?
Fed [463]

Answer:

I think the correct answer would be 6.

Hope that was helpful.Thank you!!!:)

8 0
4 years ago
(e) A 0.050 mol sample of a hydrocarbon was burned in excess oxygen.
LenKa [72]

The correct answer is 0.15.

We are aware that there is 0.05 mol of an unidentified hydrocarbon we will refer to as "X" and that its burning produces 6.6 g of carbon dioxide and 3.6 g of water.

These quantities might be converted to moles by applying the following formula:

amount= mass/ relative atomic mass

Thus, the following equation may be written for H2O: moles = 3.6 / 18 = 0.2 and for CO2: moles = 6.6 / 44 = 0.15.

0.05X + x'O2 = 0.15CO2 + 0.2H2O

This may be made simpler by dividing through by 0.05 (this step is likely to be the most helpful to you), resulting in:

1 x + x O2 = 3 co2 + 4 H2O

The hydrocarbon must have been the source of all the carbon in the carbon dioxide and all the hydrogen in the water.

Accordingly, 4 x 2 = 8 moles of H and 3 x 1 = 3 moles of C.

There are 3/1 = 3 Cs and 8/1 = 8 Hs in one X molecule.

This clearly identifies C3H8 or propane as the hydrocarbon X (dividing by 1 seems unnecessary, but it illustrates the process to use if there were more than one mol of X in the first equation).

To learn more about number of moles of carbon dioxide refer the link:

brainly.com/question/12723070

#SPJ9

6 0
2 years ago
if 315mL of 1.25 M iron(ii) sulfate is added to 405mL of.95 M ammonium phosphate, what is the limiting reactant
vladimir2022 [97]

Answer:

FeSO₄ is the Limiting Reactant

Explanation:

3FeSO₄(aq) + 2(NH₄)₃PO₄ (aq) => 3(NH₄)₃PO₄(aq) + Fe₃(PO₄)(s)

315ml(1.25M)FeSO₄ + 405ml(0.95M)(NH₄)₃PO₄

=> 0.315L(1.25M)FeSO₄       +      0.405ml(0.95M)(NH₄)PO₄

=> 0.394mole FeSO₄           +      0.385mole (NH₄)PO₄

Divide by respective coefficient => the smaller value is the Limiting Reactant.

=> 0.394/3 = 0.131                      => 0.385/2 = 0.193

Smaller value is associated with FeSO₄

∴the limiting reactant is FeSO₄.

Summery:

1. convert reactant quantities to moles

2. divide reactants by respective coefficients of balanced equation

3. note smaller value after dividing by respective coefficient => Limiting Reactant.

7 0
3 years ago
What is the density of aluminum in grams per cubic centimeter?
oksano4ka [1.4K]

Answer:

Density of aluminum is 2.699 g/cm^3

Explanation:

Density of a given material can be defined as the mass of the substance present in a unit volume. Mathematically it can be expressed as:

Density = \frac{Mass}{Volume}

Units: g/cm^3 or kg/m^3

Aluminum (Al) is one the lightest element and is known to have a density of 2.699 g/cm^3

5 0
3 years ago
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