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elixir [45]
3 years ago
15

What type of correlation would be expected between distance run and calories burned? Would this relationship be causal?positive

correlation, not causal
positive correlation, causal
negative correlation, not causal
negative correlation, causal
Mathematics
2 answers:
jek_recluse [69]3 years ago
7 0
It would be a positive correlation, casual.

Because as you run you burn more calories, everytime you do it.
Vlad [161]3 years ago
4 0
<h3><u>Answer:</u></h3>

The type of correlation that is expected between distance run and calories burned is:

positive correlation, causal

<h3><u>Step-by-step explanation:</u></h3>

A casual relation is one in which the occurrence of one event leads to the occurrence of the other.

A positive correlation is one when if there is a increase in the value of one variable then the value of the second variable also increases.

Now, if a person will run more distance then obviously it will lead to the burn of calories and also with the increase in distance the amount of calories burned will also increase.

Hence, the relation that holds between the two variable i.e. distance run and calories burned is:

Positive correlation, casual.

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Stanley has a collection of seashells. He found 35% of his collection on Florida beaches. If Stanley has 49 seashells from Flori
m_a_m_a [10]

Answer:

The number of seashells he have in his collection all together is <u>140</u>.

Step-by-step explanation:

Given:

Stanley has a collection of seashells. He found 35% of his collection on Florida beaches.

Stanley has 49 seashells from Florida.

Now, to find the number of seashells of his collection altogether.

Let the number of seashells all together be x.

Percentage of seashells found on Florida beaches = 35%.

Number of seashells found on Florida beaches = 49.

Now, to get the number of seashells altogether we put an equation:

35\%\ of\ x=49.

⇒ \frac{35}{100} \times x=49

⇒ 0.35\times x=49

⇒ 0.35x=49

Dividing both sides by 0.35 we get:

⇒ x=140.

Therefore, the number of seashells he have in his collection all together is 140.

4 0
3 years ago
Figure B is a scaled copy of Figure A.
elixir [45]

Answer:

The scale factor would be 1/2.

Step-by-step explanation:

2 of the sides both are 4 units.

If you go to figure B, it got smaller.

So in this case, you would divide.

On figure B, 2 of the sides are 2 units.

If you did it in reverse, you would get 2 because 2 times 2 is 4.

But we divide, so 4/2 is 2, so the scale factor would be:

1/2

Hope this helped!

And brainliest pls :)

6 0
2 years ago
Two standard 6 sided dice are rolled. One is purple and one is green. What is the probability that sum of the two dice on a roll
lana [24]

Answer:

1/6

Step-by-step explanation:

As the purple die has already rolled and the number landed is 6, to find the probability of the sum of the dice being 7, there is only one option for the yellow die:

purple result + yellow result = 7

6 + yellow result = 7

yellow result = 1

So the yellow die needs to roll a 1, over a total of 6 possibilities, so the probability is 1/6

5 0
3 years ago
A rectangular garden has a walk around it of width x. The garden is 20 ft by 15 ft. Write a function representing the combined w
kodGreya [7K]

Answer: A(x) = 15 ft + 2x

 

EXPLANATION

 

Given,

The dimension of the rectangular garden is 20 ft by 15 ft.

Dimension of a rectangle is written as Length by Width

This implies that,

Length of the garden = 20 ft

Width of the garden = 15 ft

 

The garden has a walk around it of width x.

The combined width of the garden = Width of garden + 2x

[we are adding twice the width of the walk because it is around the garden (this means it will add to the width of the garden on both the left and right sides)]

 

Combined width of the garden, A(x) = Width of garden + 2x

Since width of the garden = 15 ft

A(x) = 15 ft + 2x

5 0
3 years ago
Darren and barb each tried to evaluate 6(2) + 4 ÷ 2 who elaluated the expression correctly?
arlik [135]

Answer:

14

Step-by-step explanation:

6(2)

12

4÷2

2

12+2

pemdas

7 0
3 years ago
Read 2 more answers
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