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elixir [45]
3 years ago
15

What type of correlation would be expected between distance run and calories burned? Would this relationship be causal?positive

correlation, not causal
positive correlation, causal
negative correlation, not causal
negative correlation, causal
Mathematics
2 answers:
jek_recluse [69]3 years ago
7 0
It would be a positive correlation, casual.

Because as you run you burn more calories, everytime you do it.
Vlad [161]3 years ago
4 0
<h3><u>Answer:</u></h3>

The type of correlation that is expected between distance run and calories burned is:

positive correlation, causal

<h3><u>Step-by-step explanation:</u></h3>

A casual relation is one in which the occurrence of one event leads to the occurrence of the other.

A positive correlation is one when if there is a increase in the value of one variable then the value of the second variable also increases.

Now, if a person will run more distance then obviously it will lead to the burn of calories and also with the increase in distance the amount of calories burned will also increase.

Hence, the relation that holds between the two variable i.e. distance run and calories burned is:

Positive correlation, casual.

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Unit 3, Lesson 7
aksik [14]

Answer:

Find the complete table in attached file.

Step-by-step explanation:

Find the Incomplete table in attached file

Given:

A car travels 55 miles per hour for 2 hours.

So the speed of the car 55 miles per hour is constant for 2 hours.

Using speed  formula.

Speed=\frac{distance}{time}

Second row.

From the second row of the table time = \frac{1}{2}=0.5\ sec and speed is constant speed = 55\ mi/hr, so we need to find only distance.

Speed=\frac{distance}{time}

55=\frac{distance}{0.5}

distance = 55\times 0.5

distance = 27.5\ mi

Third row.

From the third row of the table time =1\frac{1}{2}=\frac{3}{2} = 1.5\ sec and speed is constant speed = 55\ mi/hr, so we need to find only distance.

Speed=\frac{distance}{time}

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Fourth row.

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Speed=\frac{distance}{time}

time=\frac{distance}{speed}

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time = 2\ sec

Therefore we complete the table from the above calculation.

8 0
3 years ago
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