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Hatshy [7]
3 years ago
14

Solve for x: 2 over 3 (x - 2) = 4x. A. negative 2 over 5 B. negative 5 over 2 C. 2 over 5 D. 5

Mathematics
2 answers:
DochEvi [55]3 years ago
7 0
4x=2/3(x - 2)
4x=2/3x - 4/3 
 4x - 2/3x=4/3
 4x - 2/3x=-4/3 
10/3x=-4/3
x=-4/3 * 3/10 

x=-12/30 
x=- 2/5 
hope this helps
xeze [42]3 years ago
6 0
2/3(x - 2) = 4x....distribute thru the parenthesis
2/3x - 4/3 = 4x...subtract 2/3x from both sides
-4/3 = 4x - 2/3x
-4/3 = 12/3x - 2/3x
-4/3 = 10/3x
-4/3 * 3/10 = x
-12/30 = x
- 2/5 = x <==
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7 0
3 years ago
Question :-
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\qquad\qquad\huge\underline{{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  \bigg( \dfrac{1}{ \sqrt{7 +  \sqrt{5} } }  +  \sqrt{7 +  \sqrt{5} } \bigg) {}^{2}

\qquad \sf  \dashrightarrow \:  \bigg( \dfrac{1}{ \sqrt{7 +  \sqrt{5} } } \bigg ) {}^{2}  +  \bigg( \sqrt{7 +  \sqrt{5} } \bigg) {}^{2}  + 2 \cdot \dfrac{1}{ \sqrt{7 +  \sqrt{5} } }  \cdot \sqrt{7 +  \sqrt{5} }

\qquad \sf  \dashrightarrow \: \dfrac{1}{7 +  \sqrt{5} }  + 7 +  \sqrt{5}  + 2

\qquad \sf  \dashrightarrow \: \dfrac{49 + 7 \sqrt{5} + 7 \sqrt{5} + 5 + 14 + 2 \sqrt{5}   }{7 +  \sqrt{5} }

\qquad \sf  \dashrightarrow \: \dfrac{68+ 16 \sqrt{5}    }{7 +  \sqrt{5} }

5 0
2 years ago
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Answer:

\frac{16}{4}, \frac{22}{7},\sqrt{5}, \sqrt{3}

Step-by-step explanation:

i got it right

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Step-by-step explanation:

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