Answer:
x = (c - k) / 3
Can you insert an image or retype the question, it is hard to read with the information that is incorrectly placed.
Answer:
306.36
Step-by-step explanation:
Answer:
(x-1)^2 + (y+4)^2 = 9
Step-by-step explanation:
We can write the equation for a circle as
(x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center and r is the radius
Substituting in (1,-4) for the center and 3 for the radius
(x-1)^2 + (y- -4)^2 = 3^2
(x-1)^2 + (y+4)^2 = 9
Answer:
![(x+3)(5x^2-2)](https://tex.z-dn.net/?f=%28x%2B3%29%285x%5E2-2%29)
Step-by-step explanation:
![5x^3+15x^2-2x-6](https://tex.z-dn.net/?f=5x%5E3%2B15x%5E2-2x-6)
The grouping method means you are going to group some terms together and then factor what you can out of each pair to hopefully make the expression you started with factorable.
Let's try it.
![5x^3+15x^2+-2x-6](https://tex.z-dn.net/?f=5x%5E3%2B15x%5E2%2B-2x-6)
I like to insert a + in front of the last two terms if it isn't already one. I think it makes it less confusing.
I'm going to group the first two terms together and I'm going to group the last two terms together like so:
![(5x^3+15x^2)+(-2x-6)](https://tex.z-dn.net/?f=%285x%5E3%2B15x%5E2%29%2B%28-2x-6%29)
Now I'm going to factor what I can out of each pairing.
![5x^2(x+3)+-2(x+3)](https://tex.z-dn.net/?f=5x%5E2%28x%2B3%29%2B-2%28x%2B3%29)
(*I always factor out negative number if the first term in the second pair has a negative on it.)
Now notice in each pairing, there is a common factor of (x+3) so I can factor that out.
The expression then becomes:
![(x+3)(5x^2-2)](https://tex.z-dn.net/?f=%28x%2B3%29%285x%5E2-2%29)