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3 years ago

PLEASE PLEASE HELP ME 40 points

Mathematics

1 answer:

Kitty [74]3 years ago

4 0

Answer:

A: x=−12

B: Since the solution is x=−12, two factors of the quadratic expression 4x2+4x+1 are (2x+1) and (2x+1).

B: Since the quadratic equation has one real solution, the graph of the quadratic equation intercepts the x-axis at (−12,0).

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It should be 17, 26, 35, 44, 53

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Find the quotient and remainder when p (x) divides with g (x) question (i) P (x) = x raise to 4 - 3 x square +4x + 5, g (x) = x

Morgarella [4.7K]

Answer: $x^2-8+\dfrac{4x+5}{x^4-3x^2+4x+5}$

Step-by-step explanation:

P(x) = x⁴ - 3x² + 4x + 5

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4 years ago

Jason opened an account at MathsWatch Bank. MathsWatch Bank’s interest rate was 4%. After one year, the bank paid him interest.

8_murik_8 [283]

Answer:

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Step-by-step explanation:

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4 years ago

What is the perimeter of triangle ABC ? 11 units 14 units 16 units 20 units Coordinate graph showing triangle A B C. Triangle A

professor190 [17]

Answer:

The perimeter is equal to $16\ units$

Step-by-step explanation:

we have that

$A(-1,1),B(2,5),C(5,1)$

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$P=AB+BC+AC$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

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$AB=\sqrt{(5-1)^{2}+(2+1)^{2}}$

$AB=\sqrt{(4)^{2}+(3)^{2}}$

$AB=\sqrt{25}$

$AB=5\ units$

step 2

Find the distance BC

$B(2,5),C(5,1)$

$BC=\sqrt{(1-5)^{2}+(5-2)^{2}}$

$BC=\sqrt{(-4)^{2}+(3)^{2}}$

$BC=\sqrt{25}$

$BC=5\ units$

step 3

Find the distance AC

$A(-1,1),C(5,1)$

$AC=\sqrt{(1-1)^{2}+(5+1)^{2}}$

$AC=\sqrt{(0)^{2}+(6)^{2}}$

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step 4

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3 years ago

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Which of the following represents a function?

Hitman42 [59]

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Step-by-step explanation:

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C has different x values so this looks promising. It passes the line test

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