Question

Bilquis is trying to find the height of a radio antenna on the roof of a local building. She stands at a horizontal distance of 29 meters from the building. The angle of elevation from her eyes to the roof ((point AA)) is 17∘
, and the angle of elevation from her eyes to the top of the antenna ((point BB)) is 31∘
. If her eyes are 1.51 meters from the ground, find the height of the antenna ((the distance from point AA to point BB)). Round your answer to the nearest meter if necessary.

Answer 1

Using relations in a right triangle, it is found that the height of the antenna is of 10 m.

What are the relations in a right triangle?

The relations in a right triangle are given as follows:

• The sine of an angle is given by the length of the opposite side to the angle divided by the length of the hypotenuse.

• The cosine of an angle is given by the length of the adjacent side to the angle divided by the length of the hypotenuse.

• The tangent of an angle is given by the length of the opposite side to the angle divided by the length of the adjacent side to the angle.

In this problem, the vertical height from her eyes to the top of the antenna is the side opposite to the angle of 17º, while the adjacent side is the horizontal distance of 29 m, hence:

$\tan{17^\circ} = \frac{h}{29}$

$h = 29\tan{17^\circ}$

$h = 8.87$

Adding the eye height:

h = 8.87 + 1.51 = 10.38 m.

Rounding to the nearest meter, the height of the antenna is of 10 m.

More can be learned about relations in a right triangle at brainly.com/question/26396675