If signs are different you subtract. So 2.5- -1.25 equals 1.25 and keep the sign of the biggest number
I’m not sure maybe 81. Sorry if I’m wrong
The answer would be B. 4,365,205. Hope I helped!
First option is correct.
Since we have given that
JKL is a right triangle.
Length of JK = 12
Length of KL = 5
By Pythagoras theorem, we get that

So, cos (L) would be
cos(L)=base/hypotenuse
cos(L)=5/13
Hence, First option is correct.
learn more about Pythagoras theorem and cosine ratios here:
brainly.com/question/9027282
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Answer:
The value of BK is 3m and the value of CK is 2.4m.
Step-by-step explanation:
Given information: ABCD trapezoid
, BC=1.2m, AD=1.8m
, AB=1.5m, CD=1.2m
, AB∩CD=K.
Using the given information draw a figure.
Two sides of a trapezoid are parallel.
Since AB∩CD=K, therefore AB and CD are not parallel, because parallel line never intersect.

(Corresponding angles)
(Corresponding angles)
By AA rule of similarity

Corresponding sides of similar triangles are proportional.






The length of BK is 3 m.




The length of CK is 2.4 m.