2rd one I could be wrong tho
Answer:

Step-by-step explanation:
we have

we know that
The formula to solve a quadratic equation of the form
is equal to
in this problem we have
so
substitute in the formula

therefore
StartFraction 19 minus StartRoot 365 EndRoot Over 2 EndFraction comma StartFraction 19 + StartRoot 365 EndRoot Over 2 EndFraction
Answer:
d≤48/2.15
Step-by-step explanation:
Step one:
Given data
Claudia spends $2.15 a day for lunch.
We are told that her balance is $48.00
let the number of days be d
Step two:
The maximum number of days she can eat is given as
d≤48/2.15
d≤22.33 days
Answer:
x = ± 
Step-by-step explanation:
Given
x² = 20 ( take the square root of both sides )
x = ± 
which can be simplified to
x = ± 2
[ ± means plus or minus ]
Answer: y=-1/5x+4
Step-by-step explanation: use the equation y=mx+b (x,y)->(5,3) 5 is an x value and 3 is a y value so you want to plug in these values into the equation. 3=-1/5(5)+b. We already know our slope so just plug it into m. Now multiply -1/5 and 5 which is -1. 3=-1+b you want to isolate b so you can find the intercept. Add one to both sides so it cancels out. 4=b we found our y-intercept so we can write the equation now. y=-1/5x+4