Answer:
we need to prove : for every integer n>1, the number 
is a multiple of 5.
1) check divisibility for n=1, 
(divisible)
2) Assume that 
is divisible by 5, 
3) Induction,
Now, 
Take out the common factor,
(divisible by 5)
add both the sides by f(k)
We have proved that difference between 
and is divisible by 5.
so, our assumption in step 2 is correct.
Since is divisible by 5, then must be divisible by 5 since we are taking the sum of 2 terms that are divisible by 5.
Therefore, for every integer n>1, the number is a multiple of 5.
Answer:
They are all ready rounded to the nearest Hundred ??
Step-by-step explanation:
They are already
Answer:
3 and 11
Step-by-step explanation:
Given 2 sides with third side x , then
difference of 2 sides < x < sum of 2 sides , that is
7 - 4 < x < 7 + 4
3 < x < 11
Thus the possible values the third side cannot be are 3 and 11
20% of 100 is 20. divide that by 2 to get 20% of 50. 20/2 is 10. 20% of 50 is 10. There are 10 blue marbles.
Hope it helped :)
Ali
