The types of items that cost less than $3.75 per item are Paperbacks and notebooks.
<h3>How do we determine the price of a unit item in a word problem?</h3>
The price of a unit item can be determined by dividing the total price by the number of units sold.
Given that:
Paperbacks sold 3 units for $10.65;
- 1 unit will be sold for = $10.65/3 = $3.55
Notebooks sold 4 units for $14.36;
- 1 unit will be sold for = $14.36/4 = $3.59
Puzzles sold 3 units for $11.85;
- 1 unit will be sold for = $11.85/3 = $3.95
Picture frame sold 4 units for $15.20;
- 1 unit will be sold for = $15.20/4 = $3.80
Therefore, from the above calculations, we can conclude that the types of items that cost less than $3.75 per item are Paperbacks and notebooks.
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Answer:
n = 60.22
Step-by-step explanation:
Hello
To find Sn, we need to draw out equations for each a₇ and a₁₉
In an arithmetic progression,
Sn = a + (n-1)d
Where Sn = sum of the A.P
a = first term
d = common difference
a₇ = 32
32 = a + (7-1)d
32 = a + 6d ........equation (i)
a₁₉ = 140
140 = a + (19-1)d
140 = a + 18d .........equation (ii)
Solve equation (i) and (ii) simultaneously
From equation (i)
32 = a + 6d
Make a the subject of formula
a = 32 - 6d .....equation (iii)
Put equation (iii) into equation (ii)
140 = (32 - 6d) + 18d
140 = 32 - 6d + 18d
Collect like terms
140 - 32 = 12d
12d = 108
d = 108 / 12
d = 9
Put d = 9 in equation (i)
32 = a + 6(9)
32 = a + 54
a = 32 - 54
a = -22
When Sn = 511
Sn = a + (n - 1)d
Substitute and solve for n
511 = -22 + (n-1) × 9
511 = -22 + 9n - 9
511 = -31 + 9n
511 + 31 = 9n
542 = 9n
n = 542 / 9
n = 60.22
Use doubling and halving to solve. So halve 12 and double 50. Then solve. 6*100=600
Answer:
$16,666.67
Step-by-step explanation:
PMT= PV*i Where PMT is the withdrawals ,PV is present value and i is the dicounting rate
PMT = $1,000.00
PV= ?
i = 6%
hence $1,000 = PV*6%
PV=1,000/6%
PV = 16,666.67
Answer:
Step-by-step explanation:
circumference=2πr
=2*3.14*2
=12.56 km