<span>Both the mushroom and the gecko are heterotrophs: they need to acquire their food from other sources. The tree, on the other hand, is an autotroph--it gains most of its nutritional needs through photosynthesis.</span>
Answer:
godzilla wins
Explanat
es jodidamente enorme y considerado un dios. también dijo chupa mi banana
Answer:
This question have two parts.
Question 1. Is a 0.185 M aqueous solution of sodium sulfate, Na2SO4, hypertonic, hypotonic or isotonic to red blood cells?
Answer:
Hypotonic because sodium sulfate is a detergent which can cross the lipid bi-layer.
Question 2. If normal red blood cells were suspended in this Na2SO4 solution, what would be the expected outcome?
Answer:
Hemolysis (Bursting of Red blood cells) will occur due to excessive movement of water inside the cell resulting from sodium sulfate solution.
if you are interested to know more according to scientist read this research paper.
Ann N Y Acad Sci. 2005 Jun;1048:451-2.
Answer:
C
Explanation:
The line is positively going up, they both will increase
Answer:
ΔG'° for the coupled reaction = -16.7 kJ/mol
<em>Note: The question is missing some parts. The complete question is as follows:</em>
<em>The first reaction in glycolysis is the phosphorylation of glucose:
</em>
<em>
Pi+glucose⟶glucose−6−phosphate+H2O
</em>
<em>This is a thermodynamically unfavorable process, with ΔG∘′= +13.8kJ/mol. In a liver cell at 37 ∘C the concentrations of both phosphate and glucose are normally maintained at about 5 mM each.</em>
<em>This very low concentration of the desired product would be unfavorable for glycolysis. In fact the reaction is coupled to ATP hydrolysis to give the overall reaction: ATP + glucose → glucose-6-phosphate + ADP + H+</em>
<em>What is the ΔG'° for the coupled reaction?</em>
Explanation:
The coupling of ATP hydrolysis which is a thermodynamically favourable reaction to the phosphorylation of glucose makes it favourable. Since the two reactions constitute a sequential reaction, their standard free energy changes are additive.
For ATP hydrolysis: ATP + H₂O ---> ADP + Pi ; ΔG'° = -30.5KJ/mol
For phosphorylation of glucose: Pi + glucose⟶glucose−6−phosphate + H2O ; ΔG'° = +13.8 kJ/Mol
For the overall reaction: ATP + glucose → glucose-6-phosphate + ADP + H⁺ ; ΔG'° = 13.8 + (-30.5) kJ/mol = -16.7 kJ/mol
Therefore, ΔG'° for the coupled reaction = -16.7 kJ/mol
