Answer:
Please find the punnet square to this question as an attachment
F1 generation:
genotype = BW
Phenotype = Erminette offsprings
F2 generation:
genotype = BB (1): BW(2): WW(1)
Phenotype = 1 Black, 2 Erminette, 1White
Explanation:
This question involves a gene coding for feather color in chickens. The allele for black feathers (B) is codominant with the allele for white feathers (W) to form an erminette chicken (black and white speckles).
According to this question, a cross between a chick with black (BB) feathers and chicken with white (WW) feathers will result in an all erminette chicken (BW) in the F1 generation (see attached image)
Also, in the F2 generation got by self-crossing the Erminette genotype in the F1 generation (BW), the following genotypic and phenotypic ratios are observed:
Genotypic ratio = BB (1): BW(2): WW(1)
Phenotypic ratio = 1 Black, 2 Erminette, 1White
Answer:
1500
Explanation:
Let's assume that the allele for yellow seed color is "Y" and the allele for green seed color is "y". Genotype of pure breeding yellow seeded plant would be "YY" and that of the green seeded plant would be "yy". A cross between YY and yy gives all heterozygous yellow seeded plants (Yy) in F1 progeny. Self pollination of two F1 plants (Yy x Yy) obtains F2 generation in 3 yellow: 1 green ratio.
The total population size of F2 generation = 2000
The proportion of yellow seeded plants in F2 generation = 3/4 (since the F2 phenotype ratio is given 3 yellow: 1 green)
Therefore, total number of yellow seeded plants in F2 progeny = 3/4 x 2000= 1500
A, B, D
Cellular respiration is the process responsible for converting chemical energy, and the reactants/products involved in cellular respiration are oxygen, glucose (sugar), carbon dioxide, and water. While the exact steps involved in cellular respiration may vary from species to species, all living organisms perform some type of cellular respiration. Without cellular respiration, living organisms wouldn’t be able to produce the chemical energy they need
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