Which theorem or postulate proves the two triangles are similar?
1 answer:
Answer:
The corresponding pair of sides are in the same ratio.
Step-by-step explanation:
For two triangles to be similar, the theorem that is required is the corresponding sides of the two triangles are in the same ratio.
Now, see the diagram of two triangles given with the question.
The ratios of the corresponding sides are
If two pairs corresponding sides are in 5 : 4 ratio, then the third pair of corresponding sides will also be in 5 : 4 ratio.
Therefore, the two triangles are similar. (Answer)
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Answer:
C
Step-by-step explanation:
General Form of an equation of a line is given by:
Where,
m is the slope, and
b is the y-intercept (point where line cuts the y-axis)
Also, parallel lines have equal slopes.
Equation of first plane is given as
Comparing this with general form of a line, we see that 3.67 is the slope and 4.81 is the y-intercept.
<em>The </em><em>second plane </em><em>is going </em><em>parallel</em><em> to this. So slope should be same. Hence </em><em>second plane has slope of 3.67. </em><em>We can write:</em>
<em></em>
<u>To find the equation of second plane</u>, we need to solve for c. Also, a point given for second plane is , substituting these values into the equation we got, we get the value of c:
We already know m and now we know c, so we can write final equation as:
Answer choice C is right.
Answer:
38 units.
Step-by-step explanation:
4x + 6 = {midpoint theorem}
4x + 6 =
4x + 6 = 2x + 22
4x -2x + 6 = 22
2x + 6 = 22
2x = 22 -6
2x = 16
x = 16/2
x = 8
Length of midsegment = 4x + 6 = 4*8 + 6
= 32 + 6
= 38