If the half-life is t, then every t days, the amount of the radioactive isotope will be cut in half.
(1/2)^(number of half-lives) = 3%
number of half-lives = ln(0.03) / ln(0.5)
This gives the number of half-lives as 5.06.
Then 300 days = (5.06)(length of 1 half-life)
length of 1 half-life = 300 / 5.06 = 59.29 days
Answer:
You can use tangent, sine, and cosine to create an equation suitable for solving this problem.
Step-by-step explanation:
Answer:
E
Step-by-step explanation:
The maximum of the data set is the point to the far right.
Point E is the maximum
Point A is the minimum
Point C is the mean
Answer: 1,004.8 cubic meters (choice D)
Work Shown:
V = (1/3)*pi*r^2*h
V = (1/3)*3.14*8^2*15
V = 1,004.8