Step-by-step explanation:
General formula for the area of a circle = πr^2.
Since the diameter is 8, the radius is 4 (half of diameter)
So the area is π(4)^2 = 16π.
Answer:
The distance from AD to BC is 7
Step-by-step explanation:
The information given are;
The type of inscribed quadrilateral ABCD = Isosceles trapezoid
The radius of the circle = 5
Segment AD of ABCD = 6
The median of the trapezoid ABCD = 7
Given the trapezoid theorem, the median is equal to half the length of the two bases added together, we have;
(AD + BC)/2 = 7
Which gives;
(6 + BC)/2 = 7
BC = 7×2 - 6 = 8
Therefore the distance from AD to BC is given by the distance from BC to the median line added to the distance from AD to the median line given as follows;
The distance from BC to the median = √(Radius² - (BC/2)²) = √(5² - (8/2)²) = 3
The distance from BC to the median = 3
The distance from AD to the median = √(Radius² - (AD/2)²) = √(5² - (6/2)²) = 4
Which gives;
The distance from AD to BC = 3 + 4 = 7
Answer:
(5, 5 )
Step-by-step explanation:
A translation of 4 units left means subtract 4 from the x- coordinate
A translation of 4 units up means add 4 to the y- coordinate.
(9, 1 ) → (9 - 4, 1 + 4 ) → (5, 5 )
(area of square) - (area of triangle)
We know the are of a square is equal to s^2, where s is the side length.
While the are of a right angle tringle is 1/2*base*height
Then we have,
s = 10
base = 4
height = 4
(area of square) - (area of triangle)
=> (10^2) - (1/2)(4)(4)
=> 100 - 8
=> 92
Finally we get: 92 in^2
