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1 year ago

15

1. Find the area of the shaded area of this figure:

1 answer:

statuscvo [17]1 year ago

8 0

(area of square) - (area of triangle)

We know the are of a square is equal to s^2, where s is the side length.

While the are of a right angle tringle is 1/2*base*height

Then we have,

s = 10
base = 4
height = 4

(area of square) - (area of triangle)

=> (10^2) - (1/2)(4)(4)
=> 100 - 8
=> 92

Finally we get: 92 in^2

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Reduce the ratio to its lowest form. 72:8

dmitriy555 [2]

Answer:

9:1

Step-by-step explanation:

Try to reduce the ratio further with the greatest common factor (GCF).

The GCF of 72 and 8 is 8

Divide both terms by the GCF, 8:

72 ÷ 8 = 9

8 ÷ 8 = 1

The ratio 72 : 8 can be reduced to lowest terms by dividing both terms by the GCF = 8 :

72 : 8 = 9 : 1

Therefore:

72 : 8 = 9 : 1

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Answer:
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3 years ago

Which are the solutions of the quadratic equation? x2 = –5x – 3 –5, 0 StartFraction negative 5 minus StartRoot 13 EndRoot Over 2

boyakko [2]

<u>Given</u>:

The quadratic equation is $x^{2}=-5 x-3$

We need to determine the solutions of the quadratic equation.

<u>Solution</u>:

Let us solve the equation to determine the value of x.

Adding both sides of the equation by 5x and 3, we get;

$x^{2}+5 x+3=0$

The solution of the equation can be determined using quadratic formula.

Thus, we get;

$x=\frac{-5 \pm \sqrt{5^{2}-4 \cdot 1 \cdot 3}}{2 \cdot 1}$

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Thus, the two roots of the equation are $x=\frac{-5 + \sqrt{13}}{2 }$ and $x=\frac{-5- \sqrt{13}}{2 }$

Hence, the solutions of the equation are $x=\frac{-5 + \sqrt{13}}{2 }$ and $x=\frac{-5- \sqrt{13}}{2 }$

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Answer:

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