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saw5 [17]
3 years ago
9

Help me find the GCF 93 AND 62

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
8 0
The GCF of 93 and 62 is 31
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Before leaving to visit Mexico, Levant traded 270 American dollars and received 3,000 Mexican pesos. When he returned from Mexic
Shtirlitz [24]

The question is incomplete:

Before leaving to visit Mexico, Levant traded 270 American dollars and received 3,000 Mexican pesos. When he returned from Mexico, he had 100 pesos left.

How much will he receive when he exchanges these pesos for dollars?

Answer:

9 dollars

Step-by-step explanation:

To find the amount that Levant will receive when he exchanges these pesos for dollars, you can use a rule of three using the information provided:

270 dollars   →  3,000 Mexican pesos

        x           ←  100 Mexican pesos

x=(270*100)/3,000=9 dollars

According to this, the answer is that he will receive 9 dollars.

4 0
3 years ago
List the like terms of the expression 3n+5p+2+n
IgorC [24]

Answer:only the ones that have letterers *m* are like terms

Step-by-step explanation: for example

5j+9u+3+6n+N

5j 9u 6n n are all like terms

4 0
3 years ago
What is the area of the figure shown?
Tatiana [17]
The area is 105 mm
8 0
2 years ago
Read 2 more answers
A line passes through the point (–6, –3) and has a slope of 2/3 . Which point is on the same line?
navik [9.2K]

Answer:

The point (0, 1) represents the y-intercept.

Hence, the y-intercept (0, 1) is on the same line.

Step-by-step explanation:

We know that the slope-intercept form of the line equation

y = mx+b

where

  • m is the slope
  • b is the y-intercept

Given

  • The point (-6, -3)
  • The slope m = 2/3

Using the point-slope form

y-y_1=m\left(x-x_1\right)

where

  • m is the slope of the line
  • (x₁, y₁) is the point

In our case:

  • m = 2/3
  • (x₁, y₁) = (-6, -3)

substituting the values m = 2/3 and the point (-6, -3)  in the point-slope form

y-y_1=m\left(x-x_1\right)

y-\left(-3\right)=\frac{2}{3}\left(x-\left(-6\right)\right)

y+3=\frac{2}{3}\left(x+6\right)

Subtract 3 from both sides

y+3-3=\frac{2}{3}\left(x+6\right)-3

y=\frac{2}{3}x+4-3

y=\frac{2}{3}x+1

comparing with the slope-intercept form y=mx+b

Here the slope = m = 2/3

Y-intercept b = 1

We know that the value of y-intercept can be determined by setting x = 0, and determining the corresponding value of y.

Given the line

y=\frac{2}{3}x+1

at x = 0, y = 1

Thus, the point (0, 1) represents the y-intercept.

Hence, the y-intercept (0, 1) is on the same line.

5 0
2 years ago
Need help ASAP questions below
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Can you rotate the picture or take another one? This one is really hard to read

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