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4 years ago

(-6/7) (-9/5) type as a simplified fraction ??? HELP

Mathematics

2 answers:

Llana [10]4 years ago

6 0

-3/4 -3/5

i think hopefully it is

Wittaler [7]4 years ago

4 0

Here is your answer:

In order to solve this question you have to multiply the fractions, and remember that a negative times a negative equals a positive.

$\frac{-6}{7} \times \frac{-9}{5} =$
$\frac{-6}{7} \times \frac{-9}{5} = \frac{54}{35}$
The numerator and the denominator don't have a common factor therefore cannot be reduced.
$= \frac{54}{25}$
You can also switch the improper fraction into a mixed number which would be $1\frac{19}{35}$

Therefore your answer will be "54/25 or 1 19/35."

Hope this helps!

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A bicycle store costs $4200 per month to operate. The store pays an average of $75 per bike. The average selling price of each

Lelechka [254]

Store should sell about 31 bicycle for average price of $135 each bicycle.

Step-by-step explanation:

To find bike we need Algebra to solve the equation.
when x = 1 , Y = 135 *x
When x 2 , Y = 135 *2
Formula you could apply to go for break even y = 135*x
Bicycle store pays about $4200
Algebra used for every business and working to make easy task.
It takes about 31 bicycle a month to get into break even.
Every store needs break even to not incur lost.
Break even point is equilibrium between income and expenses.

7 0

3 years ago

I'll give 100 brainly points, i just need help...plz

Solnce55 [7]

Answer:

A. $(x^{2/7})(y^{-3/5})$

Step-by-step explanation:

The numerator is:

$\sqrt[7]{x^2} = (x^2)^{1/7} = x^{2/7}\\$

The denominator is:

$\sqrt[5]{y^3} = (y^3)^{1/5} = y^{3/5}$

The fraction is equivalent to:

$\frac{x^{2/7}}{y^{3/5}} =$
$(x^{2/7})(y^{-3/5})$

Correct choice is A

4 0

3 years ago

Suppose you flip a fair coin N times. Let random variable h be the number of heads that occur. Use the normal approximation to e

Mariana [72]

Answer:

If n = 1000000, then

$P(h E [495000, 505000]) = \int\limits^{50500}_{495000} {\frac{2}{\sqrt{2000000\pi}} e^{\frac{-(k-500000)^2}{500000} }} \, dk$

If n = 10400, then

$P(h E [495000, 505000]) = \int\limits^{50500}_{495000} {\frac{2}{\sqrt{2000000\pi}} e^{\frac{-(k-500000)^2}{500000} }} \, dk$

If N = 102, then

$P(h < 40 or h > 60) = 1-P(40$

Step-by-step explanation:

Since the coin is fair, then the probability that a filp is heads is 1/2. Given N tries, the amount of heads can be approximated with a Normal distribution with mean μ = N *1/2 = N/2 and standard deviation σ = √(N*1/2 * 1/2) = √N/ 2

The density function of that random variable is given by de following formula

$f_X(k) = \frac{1}{\sqrt{2\pi} * \sigma} e^{\frac{-(k-\mu)^2}{2\sigma^2} } = \frac{2}{\sqrt{2\pi N}} e^{\frac{-2(k-N/2)^2}{N} }$