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pav-90 [236]
3 years ago
6

Find the value of X and Y in the following parallelogram.AD =X+8 D=2y +13 C=16-x CB=5y+4 AB=o​

Mathematics
1 answer:
vlada-n [284]3 years ago
6 0

Answer:

The answer is below

Step-by-step explanation:

AD = X + 8 ∠D = 2y +13 ∠C = 16 - x CB = 5y+4

In a parallelogram, consecutive angles are supplementary and opposite sides are equal.

Therefore for parallelogram ABCD, AB = CD, CB = AD

Since AD = CB (opposite sides of a parallelogram are equal):

x + 8 = 5y + 4

5y - x = 8 - 4

5y - x = 4             (1)

∠C + ∠D= 180° (consecutive angles of a parallelogram are supplementary). Therefore:

16 - x + 2y + 13 = 180

2y - x + 29 = 180

2y - x = 180 -29

2y - x = 151             (2)

To find x and y, subtract equation 1 from equation 2:

3y = -147

y = -49

Put y = -49 in equation 2

2(-49) - x = 151

x = -98 - 151

x = -249

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Calculate the average time the car took to reach each checkpoint. Record the average time in Table D of your Student Guide. The
zhuklara [117]

The average time the car took to reach each checkpoint are:

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<h3>Average time</h3>

Given:

Time  interval

1              2      3           4

2.02    3.17   4.12    4.93

2.05    3.07  3.98   4.81

2.15    3.25  4.23    5.01

Hence:

First quarter checkpoint

Average time= (2.02 + 2.05 + 2.15) / 3

Average time=6.22/3

Average time= 2.07s

Second quarter checkpoint

Average time= (3.17 +3.07 + 3.25) / 3

Average time=9.49/3

Average time = 3.16 s

Third quarter check point

Average time= (4.12 + 3.98 + 4.23) / 3

Average time=12.33/3

Average time= 4.11 s

Fourth quarter check point

Average time = (4.93 + 4.81 + 5.01) / 3

Average time=14.75/3

Average time= 4.917 s

Average time=4.92s (Approximately)

Therefore the average time the car took to reach each checkpoint are: 2.07, 3.16, 4.11, 4.92.

Learn more about average time here:brainly.com/question/19136062

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